我想从db获取数据。 vName 是vName=ADMIN_EMAIL
的列,此行包含名称为 vValue 的列。还有一个存储电子邮件地址的列,我希望获得该值并将其存储在$toEmail
中。
请有人指导我。
这是我的 php代码
$sqldata=mysqli_query($obj,"SELECT * FROM configuration WHERE vName='ADMIN_EMAIL'");
$rowcount=mysqli_num_rows($sqldata);
// $toEmail = "dev.waqas@designbee.us";
$mailHeaders = "From: " . $_POST["userName"] . "<". $_POST["userEmail"] .">\r\n";
if(mail($toEmail, $_POST["subject"], $_POST["content"], $mailHeaders)) {
echo "<p class='success'>Mail Sent.</p>";
} else {
echo "<p class='Error'>".$toEmail.".</p>";
}
答案 0 :(得分:1)
您需要使用mysql_fetch_assoc()
来获取查询结果。 mysql_num_rows()
为您提供查询结果中存在的行数。
检查以下代码。
$sqldata=mysqli_query($obj,"SELECT * FROM configuration WHERE vName='ADMIN_EMAIL'");
$rowcount=mysqli_num_rows($sqldata);
if($rowcount > 0)
{
$result = mysqli_fetch_assoc($sqldata);
$toEmail = $result['email']; // Your table column value
$mailHeaders = "From: " . $_POST["userName"] . "<". $_POST["userEmail"] .">\r\n";
if(mail($toEmail, $_POST["subject"], $_POST["content"], $mailHeaders)) {
echo "<p class='success'>Mail Sent.</p>";
} else {
echo "<p class='Error'>".$toEmail.".</p>";
}
}
答案 1 :(得分:1)
你只需要从db中获取记录,你还没有这样做:
$sqldata=mysqli_query($obj,"SELECT * FROM configuration WHERE vName='ADMIN_EMAIL'");
$rowcount=mysqli_num_rows($sqldata);
if($rowcount > 0)
{
$result = mysqli_fetch_assoc($sqldata); // fetch records
$toEmail = $result['vemail']; // Your column name
$mailHeaders = "From: " . $_POST["userName"] . "<". $_POST["userEmail"] .">\r\n";
if(mail($toEmail, $_POST["subject"], $_POST["content"], $mailHeaders)) {
echo "<p class='success'>Mail Sent.</p>";
} else {
echo "<p class='Error'>".$toEmail.".</p>";
}
}
答案 2 :(得分:0)
执行查询后需要获取数据。
$row = $sqldata->fetch_array(MYSQLI_ASSOC);
$toEmail= $row['vName']
答案 3 :(得分:0)
最好使用PDO,
try{
$con=new PDO("mysql::host=localhost;dbname=databasename;","username","password");
$query="SELECT * FROM configuration WHERE vName='ADMIN_EMAIL";
$res=$con->query($query);
$rows=$res->fetchAll(PDO::FETCH_BOTH);
$email="";
foreach($rows as $row)
{
$email.=$row["useremail"];//you get the user email in the var $email
}
//do what you want ....
}
catch(PDOException $e){
die("error:".$e->getMessage() );
}