如何在javaws playframework 2.5中获得帖子的回复

时间:2016-04-19 09:57:06

标签: java json playframework-2.5 java-ws

请帮助我,我想将json数据发送到一些使用基本身份验证的API,我希望从该API中获取响应。这是我的代码:

@Inject
WSClient ws;
public Result testWS(){
JsonNode task = Json.newObject()
            .put("id", 123236)
            .put("name", "Task ws")
            .put("done", true);

WSRequest request = ws.url("http://localhost:9000/json/task").setAuth("user", "password", WSAuthScheme.BASIC).post(task);
return ok(request.tojson);

问题是我如何从上面的ws返回并将其处理为json?因为该代码仍然是错误的。我正在使用playframework 2.5

1 个答案:

答案 0 :(得分:0)

.post(task)会生成CompletionStage<WSResponse>,因此您不能只在其上调用toJson。您必须从完成阶段获得最终响应(将其视为承诺)。请注意方法签名的更改。

import java.util.concurrent.CompletionStage;
import javax.inject.Inject;
import javax.inject.Singleton;
import com.fasterxml.jackson.databind.JsonNode;
import play.libs.Json;
import play.libs.ws.WSAuthScheme;
import play.libs.ws.WSClient;
import play.libs.ws.WSResponse;
import play.mvc.Controller;
import play.mvc.Result;
import scala.concurrent.ExecutionContextExecutor;

@Singleton
public class FooController extends Controller {

    private final WSClient ws;
    private final ExecutionContextExecutor exec;

    @Inject
    public FooController(final ExecutionContextExecutor exec,
                           final WSClient ws) {
        this.exec = exec;
        this.ws = ws;
    }

    public CompletionStage<Result> index() {
        final JsonNode task = Json.newObject()
                                  .put("id", 123236)
                                  .put("name", "Task ws")
                                  .put("done", true);

        final CompletionStage<WSResponse> eventualResponse = ws.url("http://localhost:9000/json/task")
                                                               .setAuth("user",
                                                                        "password",
                                                                        WSAuthScheme.BASIC)
                                                               .post(task);

        return eventualResponse.thenApplyAsync(response -> ok(response.asJson()),
                                               exec);
    }
}

检查documentation以获取有关使用Web服务异步调用的更多详细信息。