Question

这是我的DataFrame：

issue,received_time
aa,25-06-15 08:42:43.830000000 PM
bb,25-06-15 08:42:43.830000000 PM

我需要输出：

issue,received_time
aa,25-06-15
bb,25-06-15

Answer 1

我认为您可以使用dt.date：

df['received_time'] = df['received_time'].dt.date
print df
  issue received_time
0    aa    2015-06-25
1    bb    2015-06-25

如果列类型不是datetime，请先按to_datetime转换：

df['received_time'] = pd.to_datetime(df['received_time']).dt.date
print df
  issue received_time
0    aa    2015-06-25
1    bb    2015-06-25