我正在学习symfony 2.在文档中,我看到了多个对一个关系的例子。我尝试在我的代码中执行此操作。我有两个实体:产品和类别。
/**
* @ORM\ManyToOne(targetEntity="Category",inversedBy="products")
* @ORM\JoinColumn(name="category_id", referencedColumnName="id")
*/
private $category;
在实体产品中我有这样的代码。我执行了app\console doctrine:generate:entities AppBundle
和app\console doctrine:schema:update --force
。表类别有外观,但在表格产品中我没有字段category_id。我清除了缓存,但它没有工作。有什么问题?
产品
<?php
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
use AppBundle\Entity\Category;
/**
* Product
* @ORM\Entity
* @ORM\Table(name="product")
*/
class Product
{
/**
* @ORM\Column(type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @ORM\Column(type="string",length=100)
*/
private $name;
/**
* @ORM\Column(type="decimal", scale=2)
*/
private $price;
/**
* @ORM\Column(type="text")
*/
private $description;
/**
* @ORM\ManyToOne(targetEntity="Category", inversedBy="products")
* @ORM\JoinColumn(name="category_id", referencedColumnName="id")
*/
private $category;
/**
* Get id
*
* @return integer
*/
public function getId()
{
return $this->id;
}
/**
* Set name
*
* @param string $name
* @return Product
*/
public function setName($name)
{
$this->name = $name;
return $this;
}
/**
* Get name
*
* @return string
*/
public function getName()
{
return $this->name;
}
/**
* Set price
*
* @param integer $price
* @return Product
*/
public function setPrice($price)
{
$this->price = $price;
return $this;
}
/**
* Get price
*
* @return integer
*/
public function getPrice()
{
return $this->price;
}
/**
* Set description
*
* @param string $description
* @return Product
*/
public function setDescription($description)
{
$this->description = $description;
return $this;
}
/**
* Get description
*
* @return string
*/
public function getDescription()
{
return $this->description;
}
}
分类
<?php
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
use Doctrine\Common\Collections\ArrayCollection;
/**
* Category
* @ORM\Entity
* @ORM\Table(name="category")
*/
class Category
{
/**
* @ORM\Column(type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @ORM\Column(type="string", length=64)
*/
private $name;
/**
* @ORM\OneToMany(targetEntity="Product", mappedBy="category")
*/
private $products;
public function __construct()
{
$this->products = new ArrayCollection();
}
/**
* Get id
*
* @return integer
*/
public function getId()
{
return $this->id;
}
/**
* Set name
*
* @param string $name
* @return Category
*/
public function setName($name)
{
$this->name = $name;
return $this;
}
/**
* Get name
*
* @return string
*/
public function getName()
{
return $this->name;
}
}
php app \ console doctrine后面的UPD2 :schema:update --dump-sql
c:\xampp1\htdocs\first_project
# php app\console doctrine:schema:update --dump-sql
CREATE TABLE category (id INT AUTO_INCREMENT NOT NULL, name VARCHAR(255) NOT NUL
L, PRIMARY KEY(id)) DEFAULT CHARACTER SET utf8 COLLATE utf8_unicode_ci ENGINE =
InnoDB;
CREATE TABLE product (id INT AUTO_INCREMENT NOT NULL, name VARCHAR(128) NOT NULL
, price INT NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY(id)) DEFAULT CH
ARACTER SET utf8 COLLATE utf8_unicode_ci ENGINE = InnoDB;
COMP323 c:\xampp1\htdocs\first_project
#
答案 0 :(得分:0)
请在注释中尝试使用对Category实体的完整命名空间引用。
/**
*@ORM\ManyToOne(targetEntity="AppBundle\Entity\Category",inversedBy="products")
*@ORM\JoinColumn(name="category_id", referencedColumnName="id")
*/
答案 1 :(得分:0)
这两个在symfony 2.8(lts)中为我工作。
使用php app/console doctrine:schema:update --force --dump-sql
我删除了您可以使用以下内容生成的getter和setter:
php app/console doctrine:generate:entities AppBundle:Product
php app/console doctrine:generate:entities AppBundle:Category
<强> Product.php 强>
<?php
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
use AppBundle\Entity\Category;
/**
* Product
* @ORM\Entity
* @ORM\Table(name="product")
*/
class Product
{
/**
* @ORM\Column(type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @ORM\Column(type="string",length=100)
*/
private $name;
/**
* @ORM\Column(type="decimal", scale=2)
*/
private $price;
/**
* @ORM\Column(type="text")
*/
private $description;
/**
* @ORM\ManyToOne(targetEntity="Category", inversedBy="products")
* @ORM\JoinColumn(name="category_id", referencedColumnName="id")
*/
private $category;
<强> Category.php 强>
<?php
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
use Doctrine\Common\Collections\ArrayCollection;
/**
* Category
* @ORM\Entity
* @ORM\Table(name="category")
*/
class Category
{
/**
* @ORM\Column(type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @ORM\Column(type="string", length=64)
*/
private $name;
/**
* @ORM\OneToMany(targetEntity="Product", mappedBy="category")
*/
private $products;
public function __construct()
{
$this->products = new ArrayCollection();
}
}
上面的代码将生成以下SQL:
CREATE TABLE category (id INT AUTO_INCREMENT NOT NULL, name VARCHAR(64) NOT NULL, PRIMARY KEY(id)) DEFAULT CHARACTER SET utf8 COLLATE utf8_unicode_ci ENGINE = InnoDB;
CREATE TABLE product (id INT AUTO_INCREMENT NOT NULL, category_id INT DEFAULT NULL, name VARCHAR(100) NOT NULL, price NUMERIC(10, 2) NOT NULL, description LONGTEXT NOT NULL, INDEX IDX_D34A04AD12469DE2 (category_id), PRIMARY KEY(id)) DEFAULT CHARACTER SET utf8 COLLATE utf8_unicode_ci ENGINE = InnoDB;
ALTER TABLE product ADD CONSTRAINT FK_D34A04AD12469DE2 FOREIGN KEY (category_id) REFERENCES category (id);
答案 2 :(得分:0)
在您的产品实体中添加以下代码,然后为db和cache运行这些命令,然后您将在表中看到此列。 (通过命令创建实体时无法创建映射,因此您可以手动为这些列创建变量。)
/**
* @var categoryId
*
* @ORM\Column(name="category_id", type="integer" , nullable = false)
*/
private $categoryId;