我有这张桌子......
id name location date_created
-- ---- -------- ------------
15641 Maybel New York 2015-09-15
84194 Joseph Arkansas 2015-02-03
36479 Frank Illinois 2015-10-28
19804 Samantha San Francisco 2015-11-05
67811 Charles Texas 2015-11-05
......和这张桌子......
id name location created_at
-- ---- -------- ----------
15641 Maybel New York 2015-09-15
84194 Joseph Arkansas 2015-02-03
36479 Frank Illinois 2015-10-28
78916 Logan Philadelphia 2015-12-01
26799 George Mississippi 2015-12-10
我需要的是......
id name location created_at
-- ---- -------- ----------
19804 Samantha San Francisco 2015-11-05
67811 Charles Texas 2015-11-05
所以基本上我需要一个查询来只显示表1中未在表2中找到的记录。谢谢!
答案 0 :(得分:1)
您可以使用此
SELECT *
FROM table1
WHERE id NOT IN (SELECT id FROM table2)
答案 1 :(得分:0)
SELECT *
FROM table1 t1
Left join table2 t2 ON t1.id = t2.id
WHERE t2.id IS NULL;