Question

我有：

String s=" \"son of god\"\"cried out\" a good day and ok ";

这在屏幕上显示为：

"son of god""cried out" a good day and ok 

Pattern phrasePattern=Pattern.compile("(\".*?\")");
Matcher m=phrasePattern.matcher(s);

我希望获取所有被“”包围的短语并将其添加到ArrayList<String>。它可能有两个以上这样的短语。如何获取每个短语并放入Arraylist？

Answer 1

使用Matcher，您可以在90％的路上行驶。您只需要#find方法。

ArrayList<String> list = new ArrayList<>();
while(m.find()) {
    list.add(m.group());
}

Answer 2

另一种方法，我只建议它，因为你没有明确说你必须使用正则表达式匹配，就是在"上拆分。每一件都是你的兴趣。

public static void main(String[] args) {
    String[] testCases = new String[] {
            " \"son of god\"\"cried out\" a good day and ok ",
            "\"starts with a quote\" and then \"forgot the end quote",
    };
    for (String testCase : testCases) {
        System.out.println("Input: " + testCase);
        String[] pieces = testCase.split("\"");
        System.out.println("Split into : " + pieces.length + " pieces");
        for (int i = 0; i < pieces.length; i++) {
            if (i%2 == 1) {
                System.out.println(pieces[i]);
            }
        }
        System.out.println();
    }
}

结果：

Input:  "son of god""cried out" a good day and ok 
Split into : 5 pieces
son of god
cried out

Input: "starts with a quote" and then "forgot the end quote
Split into : 4 pieces
starts with a quote
forgot the end quote

如果您想确保偶数个双引号，请确保拆分结果有奇数。

用于包围的字符串的java正则表达式“”

2 个答案: