我有一个用作搜索框的输入框,我通过查询SQL数据库来填充选择框。例如,我的数据库中有两个名为“Dummy Organization”和“Dummy 2”的组织。因此,当用户开始键入“du”时,选择框将填充这两个组织。我想要做的是组合这两个字段:输入框(充当搜索框)和选择框(显示结果)。我的研究表明selectize.js可能有用,但由于我是js的新手,我无法弄清楚如何。有人可以帮帮我吗?我的代码如下:
从数据库获取数据的js:
<script type="text/javascript">
function searchq(){
var searchTxt = $("input[name='search']").val();
$.post("search.php", {searchVal: searchTxt},function(output4){
$("#output4").html(output4);
}
</script>
表格:
<form action="newbrand.php" method="post" id="form">
<br>
Brand Name: <input type="text" name="bname" required /><br><br>
Search for an Organization: <input type="text" required name="search" onkeyup="searchq()" id="output"><br><br>
Selected Organization:
<select id="output4" name="taskOption"></select>
</form>
search.php文件
<?php
include 'db_connect.php';
$link = mysqli_connect($host, $username, $password, $db);
if(!link){
echo "DB Connection error";
}
$output = '' ;
$output2 = '' ;
if (isset($_POST['searchVal'])){
$searchq = $_POST['searchVal'];
//$searchq = preg_replace("#[^0-9a-z]#i","",$searchq);
$query = mysqli_query($link, "SELECT * FROM `organisations_info` WHERE `Organisation_Name` LIKE '%".$searchq."%' ")or die("Could not search!");
$count = mysqli_num_rows($query);
if($count == 0){
$output = '<option>No results!</option>';
}else{
while($row = mysqli_fetch_array($query)){
$orgname = $row['Organisation_Name'];
$orgid = $row['Organisation_Id'];
$subs = $row['Subscription_Type'];
?>
<option value="<?php echo $orgid; ?>"><?php echo $orgname; ?></option>
<div><?php echo $subs; ?></div>
<?php
} // while
} // else
} // main if
?>