所以...,好吧我是初学者,所以不要太苛刻:)
我有这部分代码,我想一直执行。但是当我围绕它做一个while
循环(或任何循环)时 - 它只是执行(因此循环因某些原因而无法工作)。问题是:我怎样才能产生一个常量这个代码循环?
int main(void)
{
int temp = 0;
while (temp != 1) { //here is the loop i was trying
CURL *curl;
CURLcode res;
FILE *hd_src;
struct stat file_info;
curl_off_t fsize;
struct curl_slist *headerlist = NULL;
static const char buf_1[] = "RNFR " UPLOAD_FILE_AS;
static const char buf_2[] = "RNTO " RENAME_FILE_TO;
if (stat(LOCAL_FILE, &file_info)) {
printf("Couldnt open '%s': %s\n", LOCAL_FILE, strerror(errno));
return 1;
}
fsize = (curl_off_t)file_info.st_size;
printf("Local file size: %" CURL_FORMAT_CURL_OFF_T " bytes.\n", fsize);
hd_src = fopen(LOCAL_FILE, "rb");
curl_global_init(CURL_GLOBAL_ALL);
curl = curl_easy_init();
if (curl) {
headerlist = curl_slist_append(headerlist, buf_1);
headerlist = curl_slist_append(headerlist, buf_2);
curl_easy_setopt(curl, CURLOPT_READFUNCTION, read_callback);
curl_easy_setopt(curl, CURLOPT_UPLOAD, 1L);
curl_easy_setopt(curl, CURLOPT_URL, REMOTE_URL);
curl_easy_setopt(curl, CURLOPT_POSTQUOTE, headerlist);
curl_easy_setopt(curl, CURLOPT_READDATA, hd_src);
curl_easy_setopt(curl, CURLOPT_INFILESIZE_LARGE,
(curl_off_t)fsize);
res = curl_easy_perform(curl);
if (res != CURLE_OK)
fprintf(stderr, "curl_easy_perform() failed: %s\n",
curl_easy_strerror(res));
curl_slist_free_all(headerlist);
curl_easy_cleanup(curl);
}
fclose(hd_src);
curl_global_cleanup();
}
return 0;
}
答案 0 :(得分:0)
我通常做的无限循环是:
while(true) // In C you can also write 'while(1)'
{
// Your code
}
为了确保你的循环实际上是“循环”,只需创建一个随时增量的变量i,并将其打印出来:
int i = 0;
while(true)
{
i++;
print("Loop iteration: " + i);
// Your code here.
}
如果print语句因为变量'i'是整数而给出错误,请查看以下链接: Converting int to string in c
修改强>
如果你的程序在没有进一步细节的情况下停止,你可能会出错。我会做的是:
int i = 0;
while(true)
{
i++;
// Some code here
print("I got to this point.");
// Some more code
print("Yet another milestone reached.");
// Some more code
print("The end of loop: " + i);
}
至少你得到一些输出。你可以找出错误所在的位置。
祝你好运: - )