我有一个{"Top":[{"A":1,"B":721.0,"C":false}]}
形式的字符串,我希望将其转换为Python集合。
我尝试使用ast.literal_eval
这样:
x = '{"Top":[{"A":1,"B":721.0,"C":false}]}'
print ast.literal_eval(x)
但是,我收到此错误:
File "queryFlights.py", line 19, in <module>
print ast.literal_eval(x)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/ast.py", line 80, in literal_eval
return _convert(node_or_string)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/ast.py", line 63, in _convert
in zip(node.keys, node.values))
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/ast.py", line 62, in <genexpr>
return dict((_convert(k), _convert(v)) for k, v
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/ast.py", line 60, in _convert
return list(map(_convert, node.elts))
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/ast.py", line 63, in _convert
in zip(node.keys, node.values))
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/ast.py", line 62, in <genexpr>
return dict((_convert(k), _convert(v)) for k, v
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/ast.py", line 79, in _convert
raise ValueError('malformed string')
ValueError: malformed string
如何将该字符串转换为集合?
答案 0 :(得分:5)
false
不接受 ast.literal_eval
。
>>> ast.literal_eval('false')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/ast.py", line 80, in literal_eval
return _convert(node_or_string)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/ast.py", line 79, in _convert
raise ValueError('malformed string')
ValueError: malformed string
False
是
>>> ast.literal_eval('False')
False
但您可能希望使用json.loads
,因为您的字符串看起来像有效的json(并且json.loads
比ast.literal_eval
更快以评估json字符串)...
>>> import json
>>> x = '{"Top":[{"A":1,"B":721.0,"C":false}]}'
>>> json.loads(x)
{u'Top': [{u'A': 1, u'C': False, u'B': 721.0}]}