Question

我想打开多个csv文件（具有相同的数据类型/列），将数据保存到一个变量中，对数据执行一些操作并将其保存到一个csv文件中。虽然我可以轻松打开一个文件，但我似乎无法找到打开多个文件的方法。这是我的代码：

import numpy as np
import csv
from collections import Counter

files = ['11.csv', '12.csv', '13.csv', '14.csv', '15.csv']

with open(files) as csvfile:
    info = csv.reader(csvfile, delimiter=',')
    info_types = []
    records = 0
    for row in info:
        records = row[2]
        call_types.append(records)
stats = Counter(call_types).most_common()
print(stats)

results = stats
resultFile = open("Totals.csv",'w')
wr = csv.writer(resultFile, dialect='excel')
for output in results:
    wr.writerow(output)

Answer 1

为了使其有效，同时减少容易出错并高效尝试以下方法。

# required imports

files = ['11.csv', '12.csv', '13.csv', '14.csv', '15.csv']

with open("outfile","wt") as fw:
    writer = csv.writer(fw)
    for file in files:
        with open(file) as csvfile:
            info = csv.reader(csvfile, delimiter=',')
            info_types = []
            records = 0
            for row in info:
                # process row but don't store it
                # in any list if you
                # don't have to(that will defeat the purpose)
                # say you get processed_row
                writer.writerow(processed_row)

Answer 2

我会在循环中执行此操作。由于您在读取文件时已经附加了数据。

for f in files:
    with open(f) as csvfile:
        ...

Python 3：打开多个.csv文件

2 个答案: