Question

我有样本json对象的格式如下所示..

var result =  [{"value":"S900_Aru","family":"S400"},
              {"value":"S500_Aru","family":"S400"},
              {"value":"2610_H","family":"A650"}]

如果您看到前两个值与同一家庭相关，而第三个属于其他家庭 ...

我如何遍历这个完整的json对象，我需要提醒客户说这三个与同一个家庭无关......

请问有人请帮忙解决这个问题。非常感谢提前

Answer 1

您可以使用Array.prototype.every()：

var test = result.every(function(item, index, array){
  return item.family === array[0].family;
}); // true if all items in array have same family property set

＆＃13;

var result =  [{"value":"S900_Aru","family":"S400"},
              {"value":"S500_Aru","family":"S400"},
              {"value":"2610_H","family":"A650"}];
              
var test = result.every(function(item, index, array){
  return item.family === array[0].family;
});

alert(test);

＆＃13;

Answer 2

使用比较的简单循环。

for (var i= 1, first = result[0].family; i< result.length; i++) {
  if (result[i].family !== first) {
    alert('Family mismatch')
  }
}

Answer 3

您可以尝试类似

的内容

var jsonString = '[{"value":"S900_Aru","family":"S400"},{"value":"S500_Aru","family":"S400"},{"value":"2610_H","family":"A650"}]';
var jsonData = $.parseJSON(jsonString);

var valueArray = new Array();
$.each(jsonData, function (index, value) {
    valueArray.push(value['value']);
    if ($.inArray(value['value'], valueArray)) {
        alert('Duplicate Item');
        return;
    } else {
        // Continue
    }
});

Answer 4

var result =  [{"value":"S900_Aru","family":"S400"},
              {"value":"S500_Aru","family":"S400"},
              {"value":"2610_H","family":"A650"}]

var itemFamily = result[0].family;
var differs = false;
result.forEach(function(itm){ 
 if (itemFamily != itm.family) { 
   differs = true;
 } 
});

alert((differs)?"Not related to the same family":"Related to the same family");

Answer 5

我将存储family的第一个值并使用every来检查数组的每个元素。

value  = result[0].family;

function isSameFamily(element) {
  return element.family == value;
}

a = result.every(isSameFamily);

https://jsfiddle.net/ejd64es0/

if(a){
 alert("Same family")
}
else{
  alert("Not Same family")
}

Answer 6

您可以使用两个for循环来检查每个对象与另一个对象，并在两个系列不匹配时记录该消息。

for(var i=0;i<result.length-1;i++) {
    for(var j=1;j<result.length;j++) {
        if(result[i].family !== result[j].family)
            console.log("Families do not match");
    }
}

Answer 7

您可以使用第一个元素检查每个元素，并返回Array#every()的结果。

＆＃13;

var result = [{ "value": "S900_Aru", "family": "S400" }, { "value": "S500_Aru", "family": "S400" }, { "value": "2610_H", "family": "A650" }],
    related = result.every(function (a, i, aa) {
        return aa[0] === a;
    });

document.write(related);

＆＃13;

json与对象

7 个答案: