public static ArrayList<Register> validateUser( String uname, String password)throws Exception
{
ArrayList<Register> login = new ArrayList<Register>();
try
{
con = establishConnection();
pstmt = con.prepareStatement("SELECT uname,password FROM login WHERE uname = ? ");
pstmt.setString(1,uname);
//pstmt.setString(2, password);
ResultSet rs = pstmt.executeQuery();
if(rs.next())
{
Register reg = new Register();
reg.setUname(rs.getString(uname));
reg.setPassword(rs.getString(password));
login.add(reg);
System.out.println("password is "+rs.getString(2)+" username is "+rs.getString(1));
if(rs.getString(2).equals(password))
{
}
}
else
return login;
}
catch(SQLException ex)
{
ex.printStackTrace();
}
finally
{
try
{
if(pstmt!=null)
pstmt.close();
if(con != null)
con.close();
} catch (SQLException e)
{
e.printStackTrace();
}
}
return login;
}
public void doGet(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
String userName = request.getParameter("userName");
String password = request.getParameter("password");
PrintWriter out=response.getWriter();
if(userName == null)
{
out.println("The userName you entered is wrong");
}
if(password == null)
{
out.println("Wrong password");
}
//Get the DB connection Validation here
String feeds = null;
try {
ArrayList<Register> login = null;
if(Connector.validateUser(userName,password) != null)
{
out.println("Login successfull !!!");
out.print("The userName is "+userName+" pasword is "+password);
Gson gson = new Gson();
System.out.println(gson.toJson(Connector.validateUser(userName,password)));
out.println(Connector.validateUser(userName,password));
feeds = gson.toJson(Connector.validateUser(userName,password));
}
else
{
out.println("Authentication Failed Boss!!!");
}
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
我需要将db数据转换为json。我得到空阵列。 sendmail调用arraylist并以json格式显示数据。 对此有任何帮助。
这是该程序的输出 登录成功!!! userName是示例pasword，例如[]