Question

我最近发生了一些奇怪的事情，我使用PHP脚本从在线联系表单发送电子邮件，只是想知道是否有人可以对这个问题有所了解。

我有一个PHP脚本，我在多个网站上使用它一直工作正常，但由于一些奇怪的原因，我尝试在一个网站上使用它，它只是没有工作。

我尝试过它并最终意识到这与下面的代码部分有关：

这是代码的原始部分，通常可以正常工作，但由于某种原因无效：

$to = 'My Name <info@mydomain.com>';

然后我删除了名称位，以便代码看起来像这样：

$to = 'info@mydomain.com';

现在它通过ok发送电子邮件。

正如我所说，顶级代码通常工作正常，所以任何想法为什么这次我必须改变代码才能使它工作？

任何可能的解释都很棒：o）

这是完整的代码：

<?php

require("is_email.php"); // email validation function

//Retrieve form data.   
//GET - user submitted data using AJAX  
//POST - in case user does not support javascript, we'll use POST instead  
$name = ($_GET['name']) ?$_GET['name'] : $_POST['name'];  
$email = ($_GET['email']) ?$_GET['email'] : $_POST['email'];  
$telephone = ($_GET['telephone']) ?$_GET['telephone'] : $_POST['telephone'];
$address = ($_GET['address']) ?$_GET['address'] : $_POST['address'];
$enquiry = ($_GET['enquiry']) ?$_GET['enquiry'] : $_POST['enquiry'];
$calculation = ($_GET['calculation']) ?$_GET['calculation'] : $_POST['calculation']; 

//flag to indicate which method it uses. If POST set it to 1  
if ($_POST) $post=1;

//Server side validation for POST data
if (!$name) $errors[count($errors)] = 'Please click back and enter your name.';  
if (!$email) $errors[count($errors)] = 'Please click back and enter your email.'; 
else if (!is_email($email)) $errors[count($errors)] = 'Please click back as you may have entered an invalid email address.';
if (!$telephone) $errors[count($errors)] = 'Please click back and enter your telephone number.';
if (!$address) $errors[count($errors)] = 'Please click back and enter your address.';
if (!$enquiry) $errors[count($errors)] = 'Please click back and enter your enquiry.';
if ($calculation != '14') $errors[count($errors)] = 'Please click back and check you have correctly answered the simple calculation (in number format).';

//if the errors array is empty, send the mail  
if (!$errors) {

    //recipient - change this to your name and email  
    $to = 'info@mydomain.com';     
    //sender  
    $from = $name . ' <' . $email . '>';

    //subject and the html message  
    $subject = 'Website Enquiry: ' . $name;   
    $email_body = '  
    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"   
    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">  
    <html xmlns="http://www.w3.org/1999/xhtml">  
    <head></head>  
    <body>  
    <table cellpadding="5" style="color:#757575;">  
        <tr><td style="color:#3b5998;">Name: </td><td>' . $name . '</td></tr>  
        <tr><td style="color:#3b5998;">Email: </td><td>' . $email . '</td></tr>  
        <tr><td style="color:#3b5998;">Telephone: </td><td>' . $telephone . '</td></tr>
        <tr valign="top"><td style="color:#3b5998;">Address: </td><td>' . nl2br($address) . '</td></tr>
        <tr valign="top"><td style="color:#3b5998;">Enquiry: </td><td>' . nl2br($enquiry) . '</td></tr>  
    </table>  
    </body>  
    </html>';

    //send the mail  
    $result = sendmail($to, $subject, $email_body, $from);

    //if POST was used, display the message straight away  
    if ($_POST) {  
        if ($result) echo 'Thank you! We have received your message.<br /><br /><a href="../enquiry_form.html">OK</a>';  
        else echo 'Sorry, unexpected error. Please try again later';

        //else if GET was used, return the boolean value so that   
        //ajax script can react accordingly  
        //1 means success, 0 means failed  
        } else {  
            echo $result;     
        }

//if the errors array has values  
} else {

    //display the errors message  
    for ($i=0; $i<count($errors); $i++) echo $errors[$i] . '<br />';    
    exit;  
}

//Simple mail function with HTML header  
function sendmail($to, $subject, $email_body, $from) {  
    $headers = "MIME-Version: 1.0" . "\r\n";  
    $headers .= "Content-type:text/html;charset=iso-8859-1" . "\r\n";  
    $headers .= 'From: ' . $from . "\r\n";  

    $result = mail($to,$subject,$email_body,$headers);  

    if ($result) return 1;  
    else return 0;  
}  
?>

Answer 1

主机可能会因sendmail的要求而异，具体取决于他们使用的sendmail软件。您可以与您的托管公司联系，看看是否有任何警告使其工作或他们知道更好的格式。

Answer 2

使用此：

$mailFrom = '"My Name" <info@mydomain.com>';

FROM标签是双引号，空格是<email>

Answer 3

我编辑了我最初的问题来解释我是如何克服这个问题的。

通过PHP脚本发送电子邮件的问题？

3 个答案: