我有一个带有一些angularjs验证的Raw表单,
<form name = "sform" novalidate="true">
<table border="0">
<tr>
<td>
First name:
</td>
<td>
<input type="text" name="fname" ng-model="fname" placeholder="First Name" required="true" ng-pattern="/^[A-Za-z]*$/">
</td>
<td ng-show="sform.fname.$invalid && !sform.fname.$pristine" class="help-block">wrong name </td>
</tr>
<tr>
<td>
Last Name:
</td>
<td>
<input type="text" ng-model="lname" placeholder="last Name" required="true" ng-pattern="/^[A-Za-z]*$/">
</td>
<td ng-show= "sform.lname.$invalid && !sform.lname.$pristine" class="help-block">wrong Last name </td>
</tr>
<tr>
<td>
Email:
</td>
<td>
<input type="email" ng-model="email" placeholder="email" required="true">
</td>
<td ng-show="sform.email.$invalid && !sform.email.$pristine" class="help-block">wrong Email </td>
</tr>
<tr>
<td>
<button type="submit" ng-disabled="sform.$invalid" ng-click = "submitForm()">Submit</button>
</td>
</tr>
</table>
</form>
相关的.js文件是
far_app.js
var farLogin = angular.module('far_login',[]);
far_formcontroler.js
farLogin.controller('far_formcontrol',['$scope','$http',function($scope,$http) {
$scope.url='http://localhost/far_submit.php';
var config = {
headers : {
'Content-Type': 'application/x-www-form-urlencoded;charset=utf-8;'
}
}
// function to submit the form after all validation has occurred
$scope.submitForm = function() {
alert('our form is amazing'+$scope.fname+' '+$scope.email+' '+$scope.lname);
// check to make sure the form is completely valid
if ($scope.sform.$valid) {
$http.post($scope.url,{"name": $scope.fname, "email": $scope.email, "lname": $scope.lname},config).
success(function() {
alert('our form is amazing'+$scope.fname+' '+$scope.email+' '+$scope.lname);
})
}
else
{
alert('our form is not amazing');
}
}
}]);
我的 php文件是
<?php
header("Access-Control-Allow-Origin: *");
?>
<script type="text/javascript"> alert("this is php")</script>
<?php
?>
但是php脚本根本没有执行,并且它们在浏览器的控制台中没有错误。
我哪里出错了?
谢谢。
答案 0 :(得分:6)
在SO本身的Angular $ http帖子问题上有几个好的主题,例如看看以下帖子:How do I POST urlencoded form data with $http in AngularJS?或者这个:How can I post data as form data instead of a request payload?
注意:您需要在本地使用Web服务器运行此操作。下面的代码对我来说是“好的”,我做了以下:
php -S 0.0.0.0:8181
的php,访问了index.html:http://localhost:8181/提交了表单,它返回了一个json响应:{"status":"OK","data":{"userid":null}}
Pastebin:far_app.js,index.html,far_login.php
我使用PHP内置服务器仅用于测试目的,但是,我强烈建议您在Windows上使用 Wampp 或 Xampp 之类的东西来运行它。您也可以手动配置Apache / PHP / Mysql,但是,Wampp / Xampp非常易于安装和使用。
我重新构建了一些代码,如下所示:
angular.module('far_login',[])
.controller('far_formcontrol',['$scope','$http', function($scope, $http) {
// function to submit the form after all validation has occurred
$scope.submitForm = function() {
console.log('First Name : ' , $scope.fname);
console.log('Email : ' , $scope.email);
console.log('Last Name: ', $scope.lname);
// check to make sure the form is completely valid
if ($scope.sform.$valid) {
$http({
url: 'http://localhost:8181/far_submit.php',
method: 'POST',
headers: {'Content-Type': 'application/x-www-form-urlencoded'},
transformRequest: function(obj) {
var str = [];
for(var p in obj)
str.push(encodeURIComponent(p) + "=" + encodeURIComponent(obj[p]));
return str.join("&");
},
data: {"name": $scope.fname, "email": $scope.email, "lname": $scope.lname}
})
.then(function(response) {
console.log(response)
})
.catch(function (error) {
console.log(error);
});
} else {
alert('our form is not amazing');
}
};
}]);
这是基于Plunker的Angular doc和 far_submit.php 文件,如:
<?php
header("Access-Control-Allow-Origin: *");
header('Content-Type: application/json');
$data = [ 'status' => 'OK', 'data' => [ 'userid' => $autogeneratedUserId] ];
echo json_encode($data);
可以访问 far_submit.php