Question

{"cities":[{"city":{"id":1,"name":"Bangalore","status":"Active"}},
{"city":{"id":2,"name":"Mysore","status":"Active"}},... ]}

以上是JSON格式，这是我从JSON获取的方式，如下所示，

$city=$data['cities'];
$citycount=count($city);
for($i=0;$i<$citycount;$i++)
{
  echo $data['cities'][$i]['city']['id'];
}

现在如何在格式如下所示获取JSON值

{"result":[["id","name","status"],[1,"Bangalore","Active"],[2,"Mysore","Active"],... ]}

我正在使用核心PHP通过方法file_get_contents和json_decode

从JSON获取数据

Answer 1

试试这样。

$result = json_decode($newjson);
$result = $result->result;
$data = [];
$headers= $result[0]; // get the first row.
foreach($result as $key => $row) {
   // ignore the headers row.
   if($key != 0) {
       array_push($data, [
          $headers[0] => $row[0],
          $headers[1] => $row[1],
          $headers[2] => $row[2]
       ]);
   }
}

要在表单元素中显示这些值，例如＆＃39; dropdown＆＃39;用这个。

<select name="somename">
   <?php foreach($data as $item) { ?>
      <option><?= $item['name'] ?></option>
   <?php } ?>
</select>

Answer 2

试试这个

$json = '{"result":[["id","name","status"],[1,"Bangalore","Active"],[2,"Mysore","Active"]]} ';
$result = json_decode($json,true);
$dataArray = [];
foreach($result['result'] as $key => $value) {

   if($key != 0) {
       array_push($dataArray, [
          $result['result'][0][0] => $value[0],
          $result['result'][0][1] => $value[1],
          $result['result'][0][2] => $value[2]
       ]);
   }
}
print_r($dataArray);
exit;

Answer 3

这里有一个更动态的方法，无论你自动组合哪个头文件都无关紧要，但每行需要包含相同的数组长度非常重要。

$data = '{"result":[["id","name","status"],[1,"Bangalore","Active"],[2,"Mysore","Active"]]}';

$_data = json_decode($data);
if(!empty($_data)){
    $i = 0; //I know that the first row is the header
    foreach($_data->result as $row){
        if($i++ == 0){
            $header = $row;
            continue;
        }
        $newData[] = array_combine($header, $row);
    }
    echo '<pre>';
    print_r($newData);
}

当值为以下格式时如何获取JSON数据？

3 个答案: