Question

我需要每天根据UTC时间戳对我的表进行分区，我收到的错误为Fatal error: A PRIMARY KEY must include all columns in the table's partitioning function

我这样做，列id是INT PRIMARY KEY列date是INT存储UTC时间戳

我的表格结构DESCRIBE stats;

Field   Type    Null    Key     Default     Extra   
id      int(11) NO      PRI     NULL    auto_increment
date    int(11) YES             NULL    
.
.
.
.

创建表格结构SHOW CREATE TABLE stats

CREATE TABLE `stats` (
 `id` int(11) NOT NULL AUTO_INCREMENT,
 `date` int(11) DEFAULT NULL,
 .
 .
 .
 .
 PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=371 DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_unicode_ci

我通过php执行脚本

$today = strtotime("today midnight");
$partition = date('d_m_y',$today); 

ALTER TABLE `stats`
PARTITION BY RANGE (date) (
PARTITION p_$partition VALUES LESS THAN ($today)
)

我试过这个但是语法错误

ALTER TABLE `stats`
UNIQUE KEY (`id`)
PARTITION BY RANGE (date) (
PARTITION p_$partition VALUES LESS THAN ($today)
)

ALTER TABLE `stats`
PRIMARY KEY (`id`)
PARTITION BY RANGE (date) (
PARTITION p_$partition VALUES LESS THAN ($today)
)

ALTER TABLE `stats`
PRIMARY KEY (`id`,`date`)
PARTITION BY RANGE (date) (
PARTITION p_$partition VALUES LESS THAN ($today)
)

还尝试使用HASH但同样的错误A PRIMARY KEY must include all columns in the table's partitioning function in

ALTER TABLE stats
PARTITION BY HASH(date)
PARTITIONS 1

也尝试过这种方式，但收到错误Fatal error: Partition management on a not partitioned table is not possible

ALTER TABLE `stats` 
ADD PARTITION (
PARTITION p_$partition VALUES LESS THAN ($today)
)

请参阅并建议任何可行的方法。

由于

Answer 1

我通过将date添加到主键id来解决了这个问题。

ALTER TABLE `stats` DROP PRIMARY KEY, ADD PRIMARY KEY(`id`,`date`);

现在表已成功分区。

希望它也有助于其他人。

由于

MySQL - 分区所需的主键

1 个答案: