Question

我使用php插入评论 table.ive，给出变量 $ email ， $ starcount ， $ bookid < / strong>现在修复的值只是为了测试文件。 $ res 查询会检查是否有一行包含该图书ID和电子邮件。如果不是 $ sql 查询插入它，然后 $ nex 查询循环执行 starcount 列 book < / strong> column = $ book 。

如果我更改了文件顶部的电子邮件，它应该插入新的信息数据库并提取新的和现有的starcount，但它不会发布，它只返回已经存在的starcount。我不明白为什么它不工作....我使用数组返回我的文件。

<?php mysql_connect("localhost","root",""); mysql_select_db("FunReads"); $email = "sd"; $starcount = "2"; $bookid = "5"; $res = mysql_query("SELECT * FROM Review WHERE book_id='$bookid' AND user_email='$email'"); if (mysql_num_rows($res) != 0) { $array[]= array("starcount" => "already entered"); } else { $sql = mysql_query("INSERT INTO Review(book_id,starcount,user_email) values('.$bookid.','.$starcount.','.$email')"); $nex = mysql_query("SELECT * FROM Review WHERE book_id='$bookid'"); while($row = mysql_fetch_array($nex)){ $star = $row["starcount"]; $array[] = array("starcount" => $star); } } echo json_encode($array); //echo "[{"name":"n1","city":"NY"},{"name":"n2","city":"Paris"}, ...]

＆GT;

Answer 1

在我看来“Review”表中的“book_id”是主键，因为你试图多次添加它，系统显示错误重复键。检查错误＆amp;发表它。还要检查插入查询是否有效。

Answer 2

您不应手动传递主键值试试这个它会帮助你

<?php
 mysql_connect("localhost","root","");
 mysql_select_db("FunReads");
 $starcount="2";
 $email = "vinodh@gmail.com";
  $res=mysql_query("SELECT * FROM Review  WHERE email   ='$email'");
  if(mysql_num_rows($res)!=0){
      $array[]= array("starcount" => "already entered");
  }else{
         $sql=mysql_query("INSERT INTO Review (starcount,email)    values('.$starcount.','.$email')");
$nex=mysql_query("SELECT * FROM Review  WHERE email='$email'");
    while($row=mysql_fetch_array($nex)){
            $star = $row["starcount"];
            $array[] = array("starcount" => $star);
    }
  }
  echo json_encode($array);
 ?>

Answer 3

我刚刚更新了你的代码，它对我来说很好。

＆＃13;

<?php
mysql_connect("localhost","user","");
mysql_select_db("xyz");

$email = "hari@gmail.com";
$starcount = "2";
$bookid = "5";

$sql = "SELECT * FROM review WHERE book_id='$bookid' AND user_email='$email'";
$res = mysql_query($sql);

if (mysql_num_rows($res) != 0) {

    $array[]= array("starcount" => "already entered");

} else {
	$sql = "INSERT INTO review(book_id,starcount,user_email) values('$bookid','$starcount','$email')";
    $sql = mysql_query($sql);

    $nex = mysql_query("SELECT * FROM review WHERE book_id='$bookid'");

    while($row = mysql_fetch_array($nex)){

        $star = $row["starcount"];

        $array[] = array("starcount" => $star);

    }
}

echo json_encode($array);

＆＃13;

示例输出：

[{＆＃34;历史starcount＆＃34;：＆＃34; 2＆＃34;}，{＆＃34;历史starcount＆＃34;：＆＃34; 3＆＃34;}，{＆＃34;历史starcount＆＃34;：＆＃34; 1＆＃34;}，{＆＃34;历史starcount＆＃34;：＆＃34; 2＆＃34;}，{＆＃34;历史starcount＆＃34;：＆＃34; 1＆＃ 34;}]

我更新了插入查询，请尝试更新并进行测试。

PHP插入语句只插入1次

3 个答案: