从'String ?!'垮掉'String'只展开选项;你的意思是用'!!'吗?在迅速

时间:2016-04-17 17:19:20

标签: swift

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源代码如下:

let json = try NSJSONSerialization.JSONObjectWithData(data!, options: .AllowFragments)
                        if let blogs = json["profile_image_url"] as? String {

                            userImage = blogs//json["profile_image_url"] as! String
                            print("USER IMAGE:\(userImage)")

我如何解决这个问题

1 个答案:

答案 0 :(得分:7)

您希望在使用之前测试和解包任何Optional。这包括像as?这样的强制转型。如果可以避免使用强制解包或明确解包Optional(标有!),则会导致意外的运行时崩溃。

import Foundation

// create test data
let testJson = ["profile_image_url": "http://some.site.com/"]
var data: NSData?

// convert to NSData as JSON
do {
  data = try NSJSONSerialization.dataWithJSONObject(testJson, options: [])
} catch let error as NSError {
  print(error)
}

// decode NSData
do {
  // test and unwrap data
  if let data = data {
    let json = try NSJSONSerialization.JSONObjectWithData(data, options: .AllowFragments)
    // test and unwrap cast to String
    if let userImage = json["profile_image_url"] as? String {
      print("USER IMAGE:\(userImage)")
    }
  }
} catch let error as NSError {
  print(error)
}