如何汇总多个不同的值并在SQL中获取最大值

Question

我在Oracle SQL中使用distinct select，我想要做的是总结特定ID的所有数据。图片示例：

因此，例如，当PlayerIDFK为1时，我想在一列中总结TwoPointsMade而在另一列中总结ThrePointsMade，因此结果将是

PlayerIDFK       TwoPointsMade    ThreePointsMade
--------------------------------------------------
1                 5                  2

我现在使用的查询是：

SELECT PlayerIDFK, TwoPointMade, ThreePointMade
  FROM PlayerPerformance
  WHERE PlayerIDFK IN (SELECT DISTINCT PlayerIDFK
                         FROM PlayerPerformance);

Answer 1

我认为你可以使用groupby-clause，你可以通过playerIDFK进行分组并总结twopointsmade和threepointsmade

这样的事可能有用：

SELECT PlayerIDFK, sum(TwoPointMade), sum(ThreePointMade) FROM PlayerPerformance GROUP BY PlayerIDFK

如果你想获得最大值，你可以做一个嵌套查询，如下所示：

SELECT MAX(inside_query.m1, inside_query.m2) FROM (SELECT PlayerIDFK, sum(TwoPointMade) as m1, sum(ThreePointMade)as m2 FROM PlayerPerformance GROUP BY PlayerIDFK) as inside_query

可能有一种更优雅的方式来做，但这就是我所得到的：）

Answer 2

也许这可能会有所帮助：

SELECT * FROM ( SELECT PlayerIDFK, sum(TwoPointMade) as TwoPointMade FROM PlayerPerformance GROUP BY PlayerIDFK ORDER BY sum(TwoPointMade) DESC ) WHERE ROWNUM = 1 UNION ALL SELECT * FROM ( SELECT PlayerIDFK, sum(ThreePointMade) as ThreePointMade FROM PlayerPerformance GROUP BY PlayerIDFK ORDER BY sum(ThreePointMade) DESC ) WHERE ROWNUM = 1