自动映射和隐式转换必须比Any Ref"更具体。错误

时间:2016-04-17 14:16:11

标签: scala

根据activator-akka-cassandra示例,我创建了自己的应用程序,将数据保存到cassandra。

我将数据模型定义如下

import play.api.libs.json.Json

case class Location(lat: Double, long: Double)
object Location {
  implicit def toLocation(lat: Double, long: Double) = Location(lat, long)
}

case class LocationWithTime(location: Location, time: Long)
object LocationWithTime {
  implicit def toLocationWithTime(location: Location, time: Long) = LocationWithTime(location, time)
}

case class Ping(pingUuid: String, senPhoneNumber: String, recPhoneNumber: Set[String], locationWithTime: LocationWithTime)
object Ping {
  implicit val LocationFormat = Json.format[Location]
  implicit val LocationWithTimeFormat = Json.format[LocationWithTime]
  implicit val PingFormat = Json.format[Ping]
}

不幸的是应该保存数据的代码:

def insertPing(ping: Ping): Unit =
    session.executeAsync(insertPing.bind(ping.pingUuid, ping.senPhoneNumber, ping.recPhoneNumber,
      ping.locationWithTime.location.lat, ping.locationWithTime.location.long, ping.locationWithTime.time))

不编译并返回错误

Error:(24, 38) the result type of an implicit conversion must be more specific than AnyRef
      ping.locationWithTime.location.lat, ping.locationWithTime.location.long, ping.locationWithTime.time))
                                 ^

example data model中的案例类扩展了AnyVal。基于this我会猜测在我的情况下类似的东西也可以做到,但是我不能这样做,因为ValueClasses只能有一个参数。 我该如何解决这个问题?

1 个答案:

答案 0 :(得分:5)

虽然我不熟悉Cassandra,但我认为你的问题是bind需要Java Object s(即AnyRef s)和lat,是{ {1}}(即Java scala.Double),不是double

您可以将AnyRef包裹在scala.Double中来实现。

java.lang.Double