Question

歌手对象：

public class Singer  implements java.io.Serializable {

    public String  id ;
    public String name;
    public HashMap<String,String> songs;

    public Singer(String name,String id){
        this.id=id;
        this.name=name;
        this.songs=new HashMap<>();

    }

    public void AddingSong(String songName,String songURL){
        this.songs.put(songName,songURL);
    }
}

MainClass：

listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
                //starting the mediaPlayer Activity with the song url
                Intent intent = new Intent(getActivity(), songs_page.class);

                intent.putExtra("name",(String)listView.getAdapter().getItem(position));
                intent.putExtra("id", songs.get(listView.getAdapter().getItem(position)));

                Singer Obj=new Singer("1","Bayan");
                Obj.AddingSong("koko","[song URL here]");
                intent.putExtra("Allsongs",Obj);


                startActivityForResult(intent, 0);
            }
        });

歌曲活动：

歌手歌手=（歌手）getIntent（）。getSerializable（“Allsongs”）;

将活动中的字符串发送到另一个活动是有效的，但是当我想传递对象时，它就开始给我一个错误。

Answer 1

使用捆绑包：

Bundle data = new Bundle();
data.putSerializable("Allsongs", yourObject);

intent.putExtras(data);

然后在另一项活动中：

Intent intent = getIntent();
Bundle data = intent.getExtras();
Singer singer =(Singer) data.getSerializable("Allsongs");

Android - 在活动之间传递对象erorr

1 个答案: