使Visual Studio XAML输出与System.Windows.Markup.XamlReader

Question

我正在尝试在 Visual Studio （2015）中创建 WPF GUI ，并将创建的XAML加载到 Powershell 中，通过[System.Windows.Markup.XamlReader]::load()方法。

问题是，一些基本控件很好（在一些替换后），但是一旦在VS中配置了更多属性，在使用XAMLreader加载XAML时就会出现无穷无尽的错误。
示例 ：此question的答案在VisualStudio中运行正常，但在通过Xamlreader 加载时会产生大量错误。

• 那么，为什么不起作用？ System.Windows.Markup.XamlReader是。{ supposed遵循与VS生成的XAML相同的shema （至少它在标题中说明了。）

• 如何使VS生成的XAML与...一致兼容 XamlReader？

• 如果那是不可能的，那么加载VS是否有另一种方式 将XAML生成为Powershell？

编辑：示例：

# ~~~~~~~~~~~~ WPF ~~~~~~~~~~~~~
$Xaml = @"
<Window  
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
        xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
        xmlns:local="clr-namespace:Window3"

           Title="Window" Height="40" Width="40" ToolTip="Tooltip" Topmost="True" WindowStyle="None" AllowsTransparency="True" Background="Transparent" ResizeMode="CanResizeWithGrip" MaxWidth="100" MaxHeight="100" MinWidth="20" MinHeight="20">
    <Border BorderBrush="#FF000000" BorderThickness="1,1,1,1" CornerRadius="5,5,5,5" UseLayoutRounding="True">
    <Grid>
    <Grid.ColumnDefinitions>
         <ColumnDefinition/>
         <ColumnDefinition Width="*"/>
    </Grid.ColumnDefinitions>
    <Label x:Name="Backdrop" Grid.ColumnSpan="2" Content="Label" Margin="0,0,0,0" Foreground="{x:Null}" Background="#FFAD3838"/>
    <Button x:Name="Button1" Grid.Column="0" Content="" Margin="1" BorderThickness="0" Background="#FF3B87BD"/>
    <Button x:Name="Button2" Grid.Column="1" Content="" Margin="1" BorderThickness="0" Background="#FF59B483"/>
        </Grid>
    </Border>
</Window>
"@
#   Add Type
 Add-Type -AssemblyName PresentationCore,PresentationFramework,WindowsBase,system.windows.forms

#   read XAML
$inputXML = $Xaml -replace 'mc:Ignorable="d"','' -replace "x:N",'N'   
[XML]$script:WpfXml = $inputXML

#   Remove Class, Load Reader
$WpfXml.Window.RemoveAttribute(“x:Class”)
$Reader = New-Object System.Xml.XmlNodeReader $WpfXml
$WpfForm = [Windows.Markup.XamlReader]::Load($Reader) 
$WpfXml.SelectNodes("//*[@Name]") | %{  Set-Variable -Name ($_.Name) -Value $WpfForm.FindName($_.Name) -Scope script  }


$WpfForm.showdialog()

Answer 1

正如评论中所提到的，您提供的示例非常容易适用于非VS运行时。

1. 删除x:Class属性，因为我们没有定义相应的类
2. 删除mc:Ignorable属性，因为无法解析
3. 添加原始示例中缺少的结束</Window>标记：

$null = [System.Reflection.Assembly]::LoadWithPartialName('presentationframework')

$NodeReader = New-Object System.Xml.XmlNodeReader $([xml]@'
<Window
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
    xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
    xmlns:local="clr-namespace:ExampleWin"
    Title="Window" Height="200" Width="200" ToolTip="Tooltip" Topmost="True" WindowStyle="None" AllowsTransparency="True" Background="Transparent" ResizeMode="CanResizeWithGrip">
<Border BorderBrush="#FF000000" BorderThickness="1,1,1,1" CornerRadius="5,5,5,5" UseLayoutRounding="True">
    <Grid>
        <Label x:Name="Backdrop" Content="Label" Margin="0,0,0,0" Foreground="{x:Null}" Background="#FFAD3838"/>
        <Button x:Name="Button1" Content="" Margin="1,1,99,1" BorderThickness="0" Background="#FF3B87BD"/>
        <Button x:Name="Button2" Content="" Margin="99,1,1,1" BorderThickness="0" Background="#FF59B483"/>
    </Grid>
</Border>
</Window>
'@)

$Window = [System.Windows.Markup.XamlReader]::Load($NodeReader)
$Window.ShowDialog()



为了完整性，从回答到您链接的问题的示例：

$null = [System.Reflection.Assembly]::LoadWithPartialName('presentationframework')

$NodeReader = New-Object System.Xml.XmlNodeReader $([xml]@'
<Window
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
    xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
    xmlns:local="clr-namespace:ExampleWin"
    Title="Window" Height="200" Width="200" ToolTip="Tooltip" Topmost="True" WindowStyle="None" AllowsTransparency="True" Background="Transparent" ResizeMode="CanResizeWithGrip">
<Border BorderBrush="#FF000000" BorderThickness="1,1,1,1" CornerRadius="5,5,5,5" UseLayoutRounding="True">
<Grid>
    <Grid.ColumnDefinitions>
         <ColumnDefinition/>
         <ColumnDefinition Width="*"/>
    </Grid.ColumnDefinitions>

    <Label x:Name="Backdrop" Grid.ColumnSpan="2" Content="Label" Margin="0,0,0,0" Foreground="{x:Null}" Background="#FFAD3838"/>
    <Button x:Name="Button1" Grid.Column="0" Content="" Margin="1" BorderThickness="0" Background="#FF3B87BD"/>
    <Button x:Name="Button2" Grid.Column="1" Content="" Margin="1" BorderThickness="0" Background="#FF59B483"/>
</Grid>
</Border>
</Window>
'@)

$Window = [System.Windows.Markup.XamlReader]::Load($NodeReader)
$Window.ShowDialog()