Question

我正在尝试使用switch语句在三角形棱柱或三角形金字塔之间进行选择。当我选择1时，它告诉我值必须介于1和2之间。当我选择2时，它选择三角形金字塔并且似乎有效。

#include <stdio.h>
#include <stdlib.h>

int main()
{
    float tt, menu1, opt1, opt2, opt3, t, opt4;
    int td;
    printf("Enter: ");
    scanf("%f",&tt);
{
                printf("\nWhat geometrical figure would you like to use for Volume?\n\n");
                printf("1) Triangular Prism\n");
                printf("2) Triangular Pyramid\n");
                printf("User choice: ");
                scanf("%f", &td);
                while (td < 1 || td > 2) {
                    printf("\nUser choice must be between 1 and 2!\n\n");
                    printf("\nWhat geometrical figure would you like to use for Volume?\n\n");
                    printf("1) Triangular Prism\n");
                    printf("2) Triangular Pyramid\n");
                    printf("User choice: ");
                    scanf("%d", &td);
                }
                switch(td) {
                    case 1:
                    printf("Enter a, b, c, and h of the triangular prism in meters\n\n");
                    printf("a ");
                    scanf("%f", &opt1);
                    printf("b ");
                    scanf("%f", &opt2);
                    printf("c ");
                    scanf("%f", &opt3);
                    printf("h ");
                    scanf("%f", &opt4);
                    printf("\nWould you like to make another Volume calculation (1 for Yes, 2 for No)?");
                    scanf("%f", &menu1);
                    if (menu1 == 2) {
                        t = 0;
                        break;
                    }
                    if (menu1 < 1 || menu1 > 2) {
                        printf("\n\nUser choice must be between 1 and 2!\n\n");
                        printf("Would you like to make another Volume calculation (1 for Yes, 2 for No)?");
                        scanf("%f", &menu1);
                    }
                case 2:
                    printf("Enter a and h of the triangular pyramid\n\n");
                    printf("a ");
                    scanf("%f", &opt1);
                    printf("h ");
                    scanf("%f", &opt2);
                    printf("\nWould you like to make another Volume calculation (1 for Yes, 2 for No)?");
                    scanf("%f", &menu1);
                    if (menu1 == 2) {
                        t = 0;
                        break;
                    }
                    if (menu1 < 1 || menu1 > 2) {
                        printf("\n\nUser choice must be between 1 and 2!\n\n");
                        printf("Would you like to make another Volume calculation (1 for Yes, 2 for No)?");
                        scanf("%f", &menu1);
                    }

            }
}
            if (tt == 4) {
                printf("Enter the radius of the circle\n\n");
                printf("Radius: ");
                scanf("%f", &opt1);
                printf("\nWould you like to make another Volume calculation (1 for Yes, 2 for No)?");
                scanf("%f", &menu1);
                if (menu1 == 2) {
                    t = 0;
                }
                if (menu1 < 1 || menu1 > 2) {
                    printf("\n\nUser choice must be between 1 and 2!\n\n");
                    printf("Would you like to make another Volume calculation (1 for Yes, 2 for No)?");
                    scanf("%f", &menu1);
                }
            }
}

Answer 1

您必须非常小心："%f"中的格式代码必须与您提供的地址类型相匹配，作为附加参数：

"%d"适用于像opt1，opt2等浮动...
但是对于一个int，你需要sizeof(float)
更多组合here

如果存在不匹配，则不仅不会在您的变量中获得正确的值（因为1的浮点编码与整数1不同），但您还可能存在缓冲区溢出和内存损坏的风险（如果sizeof(int)大于gameStats = results as! [NSManagedObject]）。

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1 个答案: