我想为Oracle 11g中的主键生成7 DIGIT标识符。主键长度必须为7位。
这是我的代码:
CREATE SEQUENCE sequence_staff
MINVALUE 1
START WITH 1
INCREMENT BY 1;
CREATE TABLE Staff (
Staff_ID INT PRIMARY KEY, --Autoincrement 7 digit --PK
Surname VARCHAR2(50) NOT NULL,
Firstnames VARCHAR2(50) NOT NULL,
Phone VARCHAR2(30) NOT NULL, --D1
Address VARCHAR2(150) NOT NULL
);
目前主键是1(1位),而不是0000001(7位)。有什么想法吗?
答案 0 :(得分:1)
您必须按如下方式修改序列:
CREATE SEQUENCE sequence_staff
MINVALUE 1000000
START WITH 1000000
INCREMENT BY 1 NOCACHE NOCYCLE;
此外,您必须始终使用 sequence_staff.nextval 插入新的staff_id列。看看它是如何工作的
select sequence_staff.nextval from dual; --repeated times.
在此处详细了解序列https://docs.oracle.com/cd/B28359_01/server.111/b28310/views002.htm
编辑:
是的,有可能。按照您创建的方式创建序列:
select to_char(sequence_staff.nextval,'FM0000000') from dual;
编辑2:
此链接值得信赖。 http://stackoverflow.com/questions/14561210/creating-a-sequence-for-a-varchar2-field-in-oracle
编辑3:如果您真的想在Oracle数据库中按照自己的方式进行结果,那么您必须:
1. alter table staff modify staff_id varchar(20);
2. CREATE SEQUENCE sequence_staff
MINVALUE 1
START WITH 1
INCREMENT BY 1 NOCACHE NOCYCLE;
3. insert into staff(Staff_id, surname,firstnames, phone,address) values(to_char(sequence_staff.nextval,'FM0000000'),'Wayne','Bruce','0000','Gotham');
答案 1 :(得分:0)
CREATE TABLE staff
(
id NUMBER(7) NOT NULL,
surname VARCHAR2(50) NOT NULL,
firstnames VARCHAR2(50) NOT NULL,
phone VARCHAR2(30) NOT NULL,
address VARCHAR2(150) NOT NULL
);
ALTER TABLE Staff ADD (
CONSTRAINT staff_pk PRIMARY KEY (ID));
CREATE SEQUENCE staff_seq START WITH 1;
触发器定义:
CREATE OR REPLACE TRIGGER staff_bir
BEFORE INSERT ON Staff
FOR EACH ROW
BEGIN
SELECT staff_seq.NEXTVAL
INTO :new.id
FROM dual;
END;