Question

我的应用程序如何等到我的呼叫api完成后才能结束？

func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {

    GMSServices.provideAPIKey("AIzadGlsfR35k4BeHCXmRq3GDSQ-l_5gcD8")
    FlicAuth.sharedInstance

    //Call Api here

    application.registerUserNotificationSettings(UIUserNotificationSettings(forTypes: [.Alert, .Badge, .Sound], categories: nil))
    application.registerForRemoteNotifications()

    if(launchOptions?[UIApplicationLaunchOptionsLocationKey] != nil){
        LocationService.sharedInstance.startMonitoringLocation()
    }

    return FBSDKApplicationDelegate.sharedInstance().application(application, didFinishLaunchingWithOptions: launchOptions)
}

提前感谢

Answer 1

这是非常错误的，但对于你的问题，我有一个更好的解决方案。

创建一个与启动画面完全相同的viewController并设置为初始viewController ..在该viewController的类中执行操作，在Api成功后，您可以导航到实际屏幕或以编程方式更改根

我的“didFinishLaunchingWithOptions”如何等到调用api完成之后

1 个答案: