Question

需要进行简单的检查：如果用户存在则返回True，否则返回False。我正在尝试使用自定义json答案解决此问题，不确定它是否正确处理它。请帮帮我。

我的序列化器：

User = get_user_model()

Class UserSerializer(serializers.ModelSerializer):
    class Meta:
        model = User
        fields = (User.USERNAME_FIELD, )

我的观点：

@api_view(['GET'])
def UserViewSet(self, request):
    if request.method == 'GET':
        try:
            user = User.objects.get(username=User.USERNAME_FIELD)
            if User.DoesNotExist:
                json = {}
                json['message']= 'False'
                return Response(json)
            else:
                json = {}
                json['message']= 'True'
                return Response(json)

Answer 1

您可以使用APIView代替UserViewSet和UserSerializer。

class UserExistsView(APIView):

    def get(self, request, *args, **kwargs):
        # use this if username is in url kwargs
        username = self.kwargs.get('username') 

        # use this if username is being sent as a query parameter
        username = self.request.query_params.get('username')  

        try:
            user = User.objects.get(username=username) # retrieve the user using username
        except User.DoesNotExist:
            return Response(data={'message':False}) # return false as user does not exist
        else:
            return Response(data={'message':True}) # Otherwise, return True

Django休息框架。如果用户存在则返回True，否则返回False

1 个答案: