Question

如何忽略来自Intent Filter的特定URL集。现有过滤器。

 private ShareActionProvider mShareActionProvider;

 @Override
        public boolean onCreateOptionsMenu(Menu menu) {

        // Inflate menu resource file.
        getMenuInflater().inflate(R.menu.menu_main, menu);

        // Locate MenuItem with ShareActionProvider
        MenuItem shareItem = menu.findItem(R.id.menu_item_share);

        // Fetch and store ShareActionProvider
        mShareActionProvider  = (ShareActionProvider)shareItem..getActionProvider();


       setShareIntent(getDefaultShareIntent());    


          // Return true to display menu
        return true;

    }

 // Call to update the share intent    
 private void setShareIntent(Intent shareIntent) {
      if (mShareActionProvider != null) {
           mShareActionProvider.setShareIntent(shareIntent);
      }
 }

/** Returns a share intent */
private Intent getDefaultShareIntent(){
    Intent shareIntent = new Intent(Intent.ACTION_SEND);
    shareIntent.setType("text/plain");
    shareIntent.putExtra(Intent.EXTRA_SUBJECT, "SUBJECT");
    shareIntent.putExtra(Intent.EXTRA_TEXT,"Extra Text");
    return shareIntent;
}

使用上述过滤器，所有网址都会在应用中打开。我想忽略几个网址＆amp;它必须使用浏览器打开。要忽略的网址示例。

<intent-filter android:autoVerify="true">
    <action android:name="android.intent.action.VIEW" />

    <category android:name="android.intent.category.DEFAULT" />
    <category android:name="android.intent.category.BROWSABLE" />

    <data android:host="www.example.com" android:scheme="http" />
    <data android:host="www.example.com" android:scheme="https" />
    <data android:host="example.com" android:scheme="http" />
    <data android:host="example.com" android:scheme="https" />
</intent-filter>

以下代码会直接打开该应用。

https://www.example.com/privacy-policy
https://www.example.com/tos
https://www.example.com/faq

忽略Intent过滤器中的特定Url

0 个答案: