Question

我在android中实现片段，我遇到了问题：

public Fragment getItem(int num) {
            switch (num)
            {
                case 0:
                    NewFragment newFragment = new NewFragment();
                    //newFragment.refresh();
                    return newFragment;
                case 1:
                    HotFragment hotFragment = new HotFragment();
                    //hotFragment.refresh();
                    return hotFragment;
                default: return new ContentFragment();
            }

        }

当我点击标签主机中的按钮时，它会调用＆＃34; onCreateView＆＃34;和＆＃34; onViewCreated＆＃34;只有一次。但是我的目的可以在每次调用new NewFragment（）时回调函数来处理吗？

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
                         Bundle savedInstanceState) {
    // Inflate the layout for this fragment
    return inflater.inflate(R.layout.fragment_new, container, false);
}

@Override
public void onViewCreated(View view, Bundle savedInstanceState) {
    super.onViewCreated(view, savedInstanceState);
    //some config
}

我确实尝试过onDetach（），onAttach（），onResume（），但它不能用于我的目的

Answer 1

我真的不了解你，但是如果你想刷新你的片段，你可以这样做：

sheet["B1"] = "firstName"
sheet["C1"] = "middleName"
sheet["D1"] = "lastName"

for row in sheet.iter_rows(min_row=2, max_col=2):
    id_cell, name = row

    fullname = name.value.strip()
    namelist = fullname.split()
    firstname = namelist[0]
    lastname = namelist[-1]
    middlename = ""
    if len(namelist) >= 3:
        middlename = namelist[1]
    if len(namelist) == 4:
        lastname = " ".join(namelist[-2:])
    if middlename in ('Del', 'El', 'Van', 'Da'):
        lastname = " ".join([middlename, lastname])
        middlename = None

    name.value = firstname
    name.offset(column=1).value = middlename
    name.offset(column=2).value = lastname

wb.save("output.xlsx")

片段Android刷新

1 个答案: