尝试创建一个闪亮的应用程序时出错
我有两个使用形状文件创建的“总人口”和“人口密度”的地图。现在，我正在尝试构建一个闪亮的应用程序，以便我可以从总人口变为人口密度，并且情节应该相应地改变。当我运行代码时，我得到以下错误代码：
警告：错误：ggplot2不知道如何处理类矩阵的数据
以下是我一直在尝试使用的代码：
library(shiny)
library(ggplot2) #Loading necessary libraries
ui <- fluidPage(
selectInput("mr",
label="Type of Plot",
choices=c("Total Population", "Density"),
selected="Total Population"),
plotOutput("curv") #Giving an input name and listing out types to choose in the Shiny app
)
server <- function(input, output){
output$curv <- renderPlot({
ggplot() +
geom_polygon(data = final.plot==input$mr,
aes(x = long, y = lat, group = group, fill = Population),
color = "black", size = 0.20) +
coord_map()+
scale_fill_distiller(name="Population", palette = "YlGn")+
labs(title="Population in Australia")
}) # Output with the data file and input string to change when input changes.
}
shinyApp(ui = ui, server = server)
非常感谢任何帮助。
更新
我的数据集如下所示：
id long lat order hole piece
1 Ashmore and Cartier Islands 123.1169 -12.25333 1 FALSE 1
2 Ashmore and Cartier Islands 123.1206 -12.25611 2 FALSE 1
3 Ashmore and Cartier Islands 123.1222 -12.25861 3 FALSE 1
4 Ashmore and Cartier Islands 123.1239 -12.25528 4 FALSE 1
5 Ashmore and Cartier Islands 123.1258 -12.25333 5 FALSE 1
6 Ashmore and Cartier Islands 123.1275 -12.25619 6 FALSE 1
group Population Density
1 Ashmore and Cartier Islands.1 NA NA
2 Ashmore and Cartier Islands.1 NA NA
3 Ashmore and Cartier Islands.1 NA NA
4 Ashmore and Cartier Islands.1 NA NA
5 Ashmore and Cartier Islands.1 NA NA
6 Ashmore and Cartier Islands.1 NA NA
这存储在名为“final.plot”的DataFrame中。其他州的人口和密度值。我能够创建一个人口的静态可视化，它看起来像这样：
有一个类似的密度，我正在尝试创建闪亮的应用程序，我可以在这两个之间切换，以便情节相应地改变。现在我尝试了以下代码：
library(shiny)
library(ggplot2) #Loading necessary libraries
ui <- fluidPage(
selectInput("pop",
label="Type of Plot",
choices=c("Population", "Density"),
selected="Total Population"),
plotOutput("curv") #Giving an input name and listing out types to choose in the Shiny app
)
server <- function(input, output){
output$curv <- renderPlot({
ggplot() +
geom_polygon(data = final.plot,
aes(x = long, y = lat, group = group, fill = input$pop),
color = "black", size = 0.25) +
coord_map()+
scale_fill_distiller(name="Density", palette = "Spectral")+
labs(title="Population in Australia")
})
}
shinyApp(ui = ui, server = server)
但我收到的错误是“提供给连续比例的离散值”。
更新2： 这是我正在使用的数据集的链接： Dataset
1 个答案:
答案 0 :(得分：1)
我已经快速查看了您的代码并提出了一些建议。
1）在提供数据集时，您可以使用函数dput（） - 这会写入data.frame的文本表示，回答您问题的人可以简单地粘贴到R.例如：
dput(final.plot)
这将生成文本输出，我可以通过在输出前加final.plot <-来为数据框分配。我重新创建了您的数据框，并使用dput（）将其输出为下面的文本。现在其他用户可以迅速切入＆amp;粘贴您的数据：
请注意，此数据集有问题 - 请参阅下文
final.plot <- structure(list(id = structure(c(1L, 1L, 1L, 1L, 1L, 1L), .Label = "Ashmore and Cartier Islands", class = "factor"),
long = c(123.1169, 123.1206, 123.1222, 123.1239, 123.1258, 123.1275),
lat = c(-12.25333, -12.25611, -12.25861, -12.25528, -12.25333, -12.25619),
order = 1:6, hole = c(FALSE, FALSE, FALSE, FALSE, FALSE, FALSE),
piece = c(1L, 1L, 1L, 1L, 1L, 1L),
group = structure(c(1L, 1L, 1L, 1L, 1L, 1L),
.Label = "Ashmore and Cartier Islands.1", class = "factor"),
Population = c(NA, NA, NA, NA, NA, NA),
Density = c(NA, NA, NA, NA, NA, NA)),
.Names = c("id", "long", "lat", "order", "hole", "piece", "group", "Population", "Density"),
class = "data.frame",
row.names = c(NA, -6L))
错误“提供给连续比例的离散值”是由两个问题引起的。
i）您在“人口”和“密度”列中都传递 NA 。下面的数据框为这些列添加了一些（不切实际的）数字，当我单独运行绘图代码时，错误就被删除了。
更正玩具数据集
final.plot <- structure(list(id = structure(c(1L, 1L, 1L, 1L, 1L, 1L), .Label = "Ashmore and Cartier Islands", class = "factor"),
long = c(123.1169, 123.1206, 123.1222, 123.1239, 123.1258, 123.1275),
lat = c(-12.25333, -12.25611, -12.25861, -12.25528, -12.25333, -12.25619),
order = 1:6, hole = c(FALSE, FALSE, FALSE, FALSE, FALSE, FALSE),
piece = c(1L, 1L, 1L, 1L, 1L, 1L),
group = structure(c(1L, 1L, 1L, 1L, 1L, 1L),
.Label = "Ashmore and Cartier Islands.1", class = "factor"),
Population = c(1, 2, 3, 4, 5, 6),
Density = c(7, 3, 9, 1, 3, 6)),
.Names = c("id", "long", "lat", "order", "hole", "piece", "group", "Population", "Density"),
class = "data.frame",
row.names = c(NA, -6L))
ii）以交互方式运行时，会导致错误，因为您没有传递适当的数据来填充fill = input$pop。您应该传递final.plot $ Population或final.plot $ Density中的值，具体取决于所选内容。您将传递下拉框的输出 - “Population”或“Density”。这可以使用renderPlot中的switch语句进行更正：
# User input assigns appropriate data to selectedData which can be passed to other functions:
selectedData <- switch(input$pop,
"Population" = final.plot$Population,
"Density" = final.plot$Density)
2）如果您能提供生成您在上面的更新中显示的静态地图的代码，将会很有帮助。在调试Shiny代码时，我发现最简单的方法是首先以非交互方式运行该函数，然后将其合并到Shiny中。我尝试在下面提取您的绘图代码，但它没有产生预期的结果：
library(ggplot2) #Loading necessary libraries
library(mapproj)
library(maps)
ggplot() +
geom_polygon(data = final.plot,
[
3）我不熟悉将数据绘制到R中的地图上，但我相信您的应用需要加载库（mapproj）和库（地图）才能获得所需的结果。以上是以上所有内容：
library(shiny)
library(ggplot2) #Loading necessary libraries
#I added the two lines below:
library(mapproj)
library(map)
ui <- fluidPage(
selectInput("pop",
label="Type of Plot",
choices=list("Population", "Density"),
selected="Population"), #NOTE: Total Population changed to Population so that it selects correct default value
plotOutput("curv") #Giving an input name and listing out types to choose in the Shiny app
)
server <- function(input, output){
#You will probably want to simply import your dataframe final.plot using read.table etc:
final.plot <- structure(list(id = structure(c(1L, 1L, 1L, 1L, 1L, 1L), .Label = "Ashmore and Cartier Islands", class = "factor"),
long = c(123.1169, 123.1206, 123.1222, 123.1239, 123.1258, 123.1275),
lat = c(-12.25333, -12.25611, -12.25861, -12.25528, -12.25333, -12.25619),
order = 1:6, hole = c(FALSE, FALSE, FALSE, FALSE, FALSE, FALSE),
piece = c(1L, 1L, 1L, 1L, 1L, 1L),
group = structure(c(1L, 1L, 1L, 1L, 1L, 1L),
.Label = "Ashmore and Cartier Islands.1", class = "factor"),
Population = c(1, 2, 3, 4, 5, 6),
Density = c(7, 3, 9, 1, 3, 6)),
.Names = c("id", "long", "lat", "order", "hole", "piece", "group", "Population", "Density"),
class = "data.frame",
row.names = c(NA, -6L))
output$curv <- renderPlot({
#Assign value of selectedData based upon user input:
selectedData <- switch(input$pop,
"Population" = final.plot$Population,
"Density" = final.plot$Density)
ggplot() +
geom_polygon(data = final.plot,
aes(x = long, y = lat, group = group, fill = selectedData),
color = "black", size = 0.25) +
coord_map()+
scale_fill_distiller(name="Density", palette = "Spectral")+
labs(title="Population in Australia")
})
}
shinyApp(ui = ui, server = server)
现在您需要做的就是替换您的更新中显示的静态地图的代码，以便在您的闪亮应用中为renderPlot中的错误代码。
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