我有一个需要打印很多内容的toString,包括一个包含多个条目的Arraylist。这些条目必须用新行分隔。这是我正在使用的toString代码:
@Override
public String toString() // Displays the info for a class
{
return getCourseId() + "\n" + getCourseName() + "\n" + getCourseCode()
+ "\n" + "\n" + "Instructor" + "\n" + "-------------------------"
+ "\n" + Instructor.toString() + "\n" + "\n" + "Student Roster"
+ "\n" + "-------------------------" + "\n" + roster;
}
名单会打印,但所有条目都以括号和逗号存在于同一行。
我的教练坚持认为toString是自包含的,所以我在toString中的所有东西都必须留在那里。
名单打印如下:
@Override
public String toString() // Displays the info for a person in order
{
return getPersonId() + "\t" + getLastName() + "\t" + getFirstName()
+ "\t" + getMajor() + "\t" + getGpa();
}
目前,我得到的输出如下:
10000
College Algebra
MATH 101
Instructor
-------------------------
X00009876 Jones Jane Associate Professor Mathematics
Student Roster
-------------------------
[X00000002 Smith Sally History 2.98, X00000003 Adams Amanda Civil Engineering 3.7, X00000005 Turner Thomas Nursing 2.34]
但我希望它看起来像这样:
10000
College Algebra
MATH 101
Instructor
-------------------------
X00009876 Jones Jane Associate Professor Mathematics
Student Roster
-------------------------
X00000002 Smith Sally History 2.98
X00000003 Adams Amanda Civil Engineering 3.7
X00000005 Turner Thomas Nursing 2.34
任何建议都将不胜感激。谢谢!
答案 0 :(得分:0)
将此代码用于名册:
... + roster.stream().collect(Collectors.joining("\n"))
答案 1 :(得分:0)
使用
roster.stream().collect(Collectors.joining("\n"))
或
String.join("\n", roster)
答案 2 :(得分:0)
所以,我想出了我的问题。我不得不删除return语句并将其放在最后,这样我就可以放入for-each循环并打印我的Arraylist。这是最终代码的样子:
@Override
public String toString() // Displays the info for a class
{
System.out.print(getCourseId() + "\n" + getCourseName() + "\n" + getCourseCode()
+ "\n" + "\n" + "Instructor" + "\n" + "-------------------------"
+ "\n" + Instructor.toString() + "\n" + "\n" + "Student Roster"
+ "\n" + "-------------------------" + "\n");
roster.stream().forEach((tmp) -> { // for each student, put
System.out.println(tmp); // them on a new line
});
return "";
}