Question

我一直坚持使用GAE在我的网络应用程序中实现上传功能。在/ signup页面提交后，它会重定向到/ upload_file页面，同时它会提示错误405 Method Get不允许，我希望看到上传表单。

（参考文献：https://github.com/GoogleCloudPlatform/python-docs-samples/blob/master/appengine/blobstore/main.py）

感谢任何帮助！

主python脚本中的部分代码：

class FileUploadFormHandler(BaseHandler): 
# BaseHandler is a subclass of webapp2.RequestHandler.
    def get(self):
        # create an upload URL for the form that the user will fill out
        upload_url = blobstore.create_upload_url('/upload_file')

        self.render('upload-file.html', upload_url = upload_url)

class FileUploadHandler(blobstore_handlers.BlobstoreUploadHandler):
    def post(self):

        upload = self.get_uploads('file')[0]  ## 'file' is a var in the upload-file.html
        blob_key = upload.key()
        blob_reader = blobstore.BlobReader(blob_key) # instantiate a BlobReader for a given BlobStore value.
        locations = parsefile(blob_reader)
        img_url = generate_url(locations=locations)
        self.redirect('/view_map/%s' % img_url)

app = webapp2.WSGIApplication([('/', Home),
                           ('/signup', Register),
                           ('/login', Login),
                           ('/logout', Logout),
                           ('/upload_file', FileUploadHandler),
                           ('/view_map/([^/]+)?', ViewMap)
                           ],
                          debug=True)

Answer 1

在/ signup页面提交后，它会重定向到/ upload_file页面，同时它会提示错误405方法获取不被允许，我希望看到上传表单。

我认为这就是问题所在。注册后，您将重定向到/upload_file页面，该页面已映射到FileUploadHandler，如下所示：('/upload_file', FileUploadHandler),。现在请注意，FileUploadHandler没有获取方法来处理您的重定向。

我想要实现的是在注册后呈现您的upload_file模板（其中包含您的上传表单），并且您已经在class FileUploadFormHandler中设置了逻辑设置。因此，您应该将/upload_file路线映射到FileUploadFormHandler

在为用户填写的表单创建上传网址时，您还需要一条路由来处理对FileUploadHandler的调用。

如：

class FileUploadFormHandler(BaseHandler): 

    def get(self):
        # upload_url handles the POST call to FileUploadHandler
        upload_url = blobstore.create_upload_url('/upload')
        self.render('upload-file.html', upload_url = upload_url)

...

app = webapp2.WSGIApplication(
    [('/upload', FileUploadHandler),
     ('/upload_file', FileUploadFormHandler),
    ], debug=True)

注意：你应该提出一些不那么混乱的url路径;）

Google App Engine：405此方法不允许使用GET

1 个答案: