Question

现在我有一个大脑屁。我有这个功能：

function uplodeVirus(){
  console.log('working')
  console.log('uplodeVirus')
  var form = document.getElementsByTagName('form')[1]
  console.log(form)
  var select = form.children[0]
  console.log(select)
  for (x in select) {
    var lN = select[x].innerHTML // var linkName
    if (lN == "vspam 0.3 [OpenRelay-backdoor.vspam ] (0.003 Gb)"){
      value = select[x].value
      select[x].setAttribute("selected", "selected");
      form.submit()
      break
    }  
  }
}

不要担心它不是真正的病毒！这是一款名为奴隶黑客的游戏机器人 - 用于学习目的

无论如何，当我调用函数时：

var ip = '2.2.2.2'
var uplodeVirus = 'http://www.slavehack.com/index2.php?page=internet&var2=' + ip + '&var3=files&aktie=upload'
var currentUrl = window.location.href
console.log(currentUrl)
console.log(uplodeVirus)
if (currentUrl == uplodeVirus) { //Yes, I made sure that currentUrl = uplodeVirus
  uplodeVirus()
}

什么都没发生......但如果我从代码中取出代码并执行此操作：

if (currentUrl == uplodeVirus){ 
  console.log('working')
  console.log('uplodeVirus')
  var form = document.getElementsByTagName('form')[1]
  console.log(form)
  var select = form.children[0]
  console.log(select)
  for (x in select) {
    var lN = select[x].innerHTML // var linkName
    if (lN == "vspam 0.3 [OpenRelay-backdoor.vspam ] (0.003 Gb)"){
      value = select[x].value
      select[x].setAttribute("selected", "selected");
      form.submit()
      break
    }  
  }
}

有效!!!现在，我可以选择B，但我真的想弄清楚我做错了什么。

提前致谢！

Answer 1

您正在命名URL变量和具有相同名称的函数：/

由于在尝试调用函数之前初始化变量以保存字符串，因此调用uplodeVirus与调用uplodeVirus()相同。它没有任何意义，因为字符串不是函数。

尝试更改其中一个的名称。

字符串和函数的名称相同

1 个答案: