Question

我使用以下代码裁剪图像并保存

this.crop = function(width, height, type) {
            var imgInfo = this.imgInfo,
                c = this.eles.container,
                img = this.eles.img,
                original = new Image(),
                canvas = document.createElement('canvas');
            original.src = img.attr('src');
            canvas.width = width;
            canvas.height = height;

            var w = Math.round(c.width() * (imgInfo.aw / (imgInfo.w * imgInfo.s))),
                h = Math.round(c.height() * (imgInfo.ah / (imgInfo.h * imgInfo.s))),
                x = Math.round(-parseInt(img.css('left')) * (imgInfo.aw / (imgInfo.w * imgInfo.s))),
                y = Math.round(-parseInt(img.css('top')) * (imgInfo.ah / (imgInfo.h * imgInfo.s)));
            canvas.getContext('2d').drawImage(original, x, y, w, h, 0, 0, width, height);
            return {
                width: width,
                height: height,
                type: type || 'jpeg',
                string: canvas.toDataURL("image/" + type || 'jpeg'),
            };
        };

但是当我将其转换为图像然后上传到服务器。上传的图片为空白。

为此我使用save.php文件中的以下代码

<?php
if($_SERVER['REQUEST_METHOD'] == "POST") {
    define('UPLOAD_DIR', 'img/catalog/');

    $base64 = base64_decode(preg_replace('#^data:image/[^;]+;base64,#', '', $_POST['string']));
    $stamp = imagecreatefrompng('img/water.png');
    $im = imagecreatefromstring($base64);
    ob_start();

    $marge_right = 10;
    $marge_bottom = 10;
    $sx = imagesx($stamp);
    $sy = imagesy($stamp);

    imagecopy($im, $stamp, imagesx($im) - $sx - $marge_right, imagesy($im) - $sy - $marge_bottom, 0, 0, imagesx($stamp), imagesy($stamp));

    $file = UPLOAD_DIR . uniqid() . '.jpg';
    header('Content-type: image/');
    $success = imagejpeg($im, $file, 100);
    imagedestroy($im);
    echo "$file";

    }

?>

从PC上一切正常，但是当我从任何移动设备上传图像时，图像是空白的。当我将它缩放到最大尺寸时，一切正常。

你能告诉我哪里错了吗？

Answer 1

我改变了我的剧本。

this.data = function(width, height, filetype) {

            var self = this,
                imgInfo = self.imgInfo,
                c = self.eles.container,
                img = self.eles.img;

            var original = new Image();
                original.src = img.attr('src');

            // draw image to canvas
            var canvas = document.createElement('canvas');
                canvas.width = width;
                canvas.height = height;

            var w = Math.round((c.width() - (0 * 2)) * (imgInfo.aw / (imgInfo.w * imgInfo.s))),
                h = Math.round((c.height() - (0 * 2)) * (imgInfo.ah / (imgInfo.h * imgInfo.s))),
                x = Math.round(-(parseInt(img.css('left')) - 0) * (imgInfo.aw / (imgInfo.w * imgInfo.s))),
                y = Math.round(-(parseInt(img.css('top')) - 0) * (imgInfo.ah / (imgInfo.h * imgInfo.s)));

            canvas.getContext('2d').drawImage(original, x, y, w, h, 0, 0, width, height);

            data = {
                width: width,
                height: height,
                image: canvas.toDataURL("image/"+filetype),
                filetype: filetype
            };

            return data;
        };

现在它适用于iOS，但我有另一个问题。当我从相机上传照片时，它会自动旋转。

toDataURL（）从iOS设备返回空白图像

1 个答案: