Question

我试图使用jq来组合两个数组并遇到一些麻烦。

我试图解析netdata（netdata.firehol.org）中的数据，而我感兴趣的json响应中的两个数据都是数组的一部分。第一个数组是第二个数组中数据点的标签。

示例输入

[
  "time",
  "guest_nice", 
  "guest",
  "steal",
  "softirq",
  "irq",
  "user",
  "system",
  "nice",
  "iowait"
]
[
  1460728600,
  0,
  0,
  0,
  0.45731,
  0,
  0.25108,
  11.74702,
  48.22465,
  0
]

输入

如果您想自己抓取新数据进行测试，可以使用以下内容：

curl -s -X GET --header 'Accept: application/json' 
'http://netdata.firehol.org/api/v1/data?chart=system.cpu&after=-10&before=0&points=1&group=average&format=json&options=seconds%2Cjsonwrap' | jq '.result.labels, .result.data[]'

我试图使用map（）以及尝试将变量分配给两个数组，然后将这些对象打印出来，但一直都不成功（下图）。

代码

 | jq '.result.labels as $labels | .result.data[] as $data | .result.data[] | Label: $labels[.], data: $data[.]}'

我提前了解任何人的洞察力，因为我有点陷入困境，并且宁愿能够在jq中完成所有这一切，而不是在bash中使用for循环（如果可能的话）。

预期输出

{ ＆＃34;时间＆＃34;：＆＃34; 1460728600＆＃34;，＆＃34; guest_nice＆＃34;：＆＃34; 0＆＃34;， ... }

Answer 1

You haven't specified exactly how you want the arrays to be combined, but one approach is to use transpose, which in this case is effectively a kind of zip. For example:

$ jq -n -c '[["a","b"], [1,2]] | transpose'

yields: [["a",1],["b",2]]

If you wanted an array of objects, then with the same input,

transpose | map( { (.[0]) : .[1] } )

would yield: [{"a":1},{"b":2}]

If your jq does not have transpose, here is its definition:

# transpose a possibly jagged matrix, quickly;
# rows are padded with nulls so the result is always rectangular.
def transpose:
  [range(0; (map(length) | max)) as $j 
   | [range(0; length) as $i | .[$i][$j] ] ] ;

Alternatively, if you would prefer a very brief zip:

def zip: [range(0; .[0]|length) as $i | [.[0][$i], .[1][$i]]];

Answer 2

这是一个解决方案，它处理一般情况，其中第一个数组包含键名，以下数组包含使用转置和 from_entries

的值

  {h:.[0], v:.[1:][]}                        # {h:[keys], v:[values]}
| [.h, .v]                                   # [ [keys], [values] ] ...
| [ transpose[] | {key:.[0], value:.[1]} ]   # [ {"key":key, "value":value}, ... ]
| from_entries                               # { key:value, key:value, ... }

例如，如果此过滤器位于filter.jq且data.json包含

["time","guest_nice","guest","steal","softirq","irq","user","system","nice","iowait"]
[1460728600,0,0,0,0.45731,0,0.25108,11.74702,48.22465,0]
[1460728601,0,0,0,0.45732,0,0.25109,12.74703,49,0]

然后命令

jq -M -s -c -f filter.jq data.json

产生

{"time":1460728600,"guest_nice":0,"guest":0,"steal":0,"softirq":0.45731,"irq":0,"user":0.25108,"system":11.74702,"nice":48.22465,"iowait":0}
{"time":1460728601,"guest_nice":0,"guest":0,"steal":0,"softirq":0.45732,"irq":0,"user":0.25109,"system":12.74703,"nice":49,"iowait":0}

用jq解析netdata json输出（mulltiple数组）

2 个答案: