我按照上面的示例创建了一个" Base64编码的策略字符串"和#34;签名值"使用Java后端:http://docs.aws.amazon.com/AmazonS3/latest/API/sigv4-post-example.html
但是我的#34;签名值"与示例不符。 我错过了什么吗?
我相信getSignatureKey
和HmacSHA256
都可以,因为我在可靠来源中找到了。也许getStringToSign
不正确。
这是我的代码:
import javax.crypto.Mac;
import javax.crypto.spec.SecretKeySpec;
import org.apache.commons.codec.binary.Base64;
import static com.google.common.io.BaseEncoding.base16;
public class AwsSignatureGenerator {
public static void main(String[] args) throws Exception {
String signature = getSignature(getSignatureKey("wJalrXUtnFEMI/K7MDENG/bPxRfiCYEXAMPLEKEY",
"20151229",
"us-east-1",
"s3"));
System.out.println(signature);
}
public static String getStringToSign(){
String s3Policy = "{ \"expiration\": \"2015-12-30T12:00:00.000Z\", \"conditions\": [ {\"bucket\": \"sigv4examplebucket\"}, [\"starts-with\", \"$key\", \"user/user1/\"], {\"acl\": \"public-read\"}, {\"success_action_redirect\": \"http://sigv4examplebucket.s3.amazonaws.com/successful_upload.html\"}, [\"starts-with\", \"$Content-Type\", \"image/\"], {\"x-amz-meta-uuid\": \"14365123651274\"}, {\"x-amz-server-side-encryption\": \"AES256\"}, [\"starts-with\", \"$x-amz-meta-tag\", \"\"], {\"x-amz-credential\": \"AKIAIOSFODNN7EXAMPLE/20151229/us-east-1/s3/aws4_request\"}, {\"x-amz-algorithm\": \"AWS4-HMAC-SHA256\"}, {\"x-amz-date\": \"20151229T000000Z\" } ] }";
return new Base64().encodeAsString(s3Policy.getBytes());
}
public static byte[] HmacSHA256(String data, byte[] key) throws Exception {
String algorithm="HmacSHA256";
Mac mac = Mac.getInstance(algorithm);
mac.init(new SecretKeySpec(key, algorithm));
return mac.doFinal(data.getBytes("UTF8"));
}
public static byte[] getSignatureKey(String key, String dateStamp, String regionName, String serviceName) throws Exception {
byte[] kSecret = ("AWS4" + key).getBytes("UTF8");
byte[] kDate = HmacSHA256(dateStamp, kSecret);
byte[] kRegion = HmacSHA256(regionName, kDate);
byte[] kService = HmacSHA256(serviceName, kRegion);
byte[] kSigning = HmacSHA256("aws4_request", kService);
return kSigning;
}
public static String getSignature(byte[] key) throws Exception{
return base16().lowerCase().encode(HmacSHA256(getStringToSign(), key));
}
}
答案 0 :(得分:1)
我检查了你的政策 在base64中,它看起来像这样:
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
在JSON中,它看起来像这样:
{
"expiration": "2015-12-30T12:00:00.000Z",
"conditions": [
{
"bucket": "sigv4examplebucket"
},
[
"starts-with",
"$key",
"user/user1/"
],
{
"acl": "public-read"
},
{
"success_action_redirect": "http://sigv4examplebucket.s3.amazonaws.com/successful_upload.html"
},
[
"starts-with",
"$Content-Type",
"image/"
],
{
"x-amz-meta-uuid": "14365123651274"
},
{
"x-amz-server-side-encryption": "AES256"
},
[
"starts-with",
"$x-amz-meta-tag",
""
],
{
"x-amz-credential": "AKIAIOSFODNN7EXAMPLE/20151229/us-east-1/s3/aws4_request"
},
{
"x-amz-algorithm": "AWS4-HMAC-SHA256"
},
{
"x-amz-date": "20151229T000000Z"
}
]
}
根据您的JSON和密钥,正确的签名应为:
eb9df8c47e9c4bd6090809ed799f0146c71a10f7707aa1acc2c13e736d41ed54
根据我创建的这个应用程序 - > http://ttwd80.github.io/s3postcalculatorverify/
然而,我会跳过 x-amz-date和x-amz-meta-uuid另请注意,“file”字段必须是表单中的最后一个输入(除了提交按钮)。