Question

鉴于此http响应（Python字典）

{"status":1,"list":{"229279689":{"item_id":"229279689",
"resolved_id":"229279689",
"given_url":"http:\/\/www.grantland.com\/blog\/the-triangle\/post\/_\/id\/38347\/ryder-cup-preview",
"given_title":"The Massive Ryder Cup Preview - The Triangle Blog - Grantland",
"favorite":"0",
"status":"0",
"resolved_title":"The Massive Ryder Cup Preview",
"resolved_url":"http:\/\/www.grantland.com\/blog\/the-triangle\/post\/_\/id\/38347\/ryder-cup-preview",
"excerpt":"The list of things I love about the Ryder Cup is so long that it could fill a (tedious) novel, and golf fans can probably guess most of them.",
"is_article":"1",
"has_video":"1",
"has_image":"1",
"word_count":"3197",
"images":{"1":{"item_id":"229279689","image_id":"1",
    "src":"http:\/\/a.espncdn.com\/combiner\/i?img=\/photo\/2012\/0927\/grant_g_ryder_cr_640.jpg&w=640&h=360",
    "width":"0","height":"0","credit":"Jamie Squire\/Getty Images","caption":""}},
"videos":{"1":{"item_id":"229279689","video_id":"1",
    "src":"http:\/\/www.youtube.com\/v\/Er34PbFkVGk?version=3&hl=en_US&rel=0",
    "width":"420","height":"315","type":"1","vid":"Er34PbFkVGk"}}}}}

如何提取＆＃34; given_url＆＃34;不知道＆＃34; item_id＆＃34;预先？（两者都是位于响应顶部的键）。

Answer 1

尝试使用以下代码行：

try:
    print data['list'].values()[0]['given_url']
except IndexError:
    print "No data"

#output:
http:\\/\\/www.grantland.com\\/blog\\/the-triangle\\/post\\/_\\/id\\/38347\\/ryder-cup-preview

Answer 2

如果list：

下有多个项目，您可以使用以下代码提取所有网址

urls = [x['given_url'] for x in d['list'].itervalues() if 'given_url' in x]
print urls # ['http:\\/\\/www.grantland.com\\/blog\\/thetriangle\\/post\\/_\\/id\\/38347\\/ryder-cup-preview']

协助使用Python字典从Pocket读取列表中提取URL

2 个答案: