Question

我使用xUnit 1.9运行一堆测试用例，所有测试用例都与资源共享相同的连接，但它们分为三个不同的类别，要求连接处于三种不同的状态。

我创建了一个处理连接的fixture类和三个不同的类来保存需要三种不同连接状态的三类测试用例。

现在我相信夹具对象只能创建一次，只能通过构造函数连接一次，最后只通过Dispose方法断开一次。我做对了吗？

如何为每个类（方法组）仅设置一次连接状态，而不是每次为每个方法设置状态（通过向每个类构造函数添加代码）？

虚拟代码：

public class Fixture : IDispose
{
    public Fixture() { connect(); }
    public void Dispose() { disconnect(); }
    public void SetState1();
    public void SetState2();
    public void SetState3();
}

public class TestCasesForState1 : IUseFixture<Fixture>
{
    public void SetFixture(fix) { fix.SetState1() } // will be called for every test case. I'd rather have it being called once for each group

    [Fact]
    public void TestCase1();

    ...
}

public class TestCasesForState2 : IUseFixture<Fixture>
{
    public void SetFixture(fix) { fix.SetState2() } // will be called for every test case. I'd rather have it being called once for each group

    [Fact]
    public void TestCase1();

    ...
}

public class TestCasesForState3 : IUseFixture<Fixture>
{
    public void SetFixture(fix) { fix.SetState3() } // will be called for every test case. I'd rather have it being called once for each group

    [Fact]
    public void TestCase1();

    ...
}

Answer 1

public class Fixture : IDispose {

    public Fixture() { connect(); }

    public void Dispose() { disconnect(); }

    static bool state1Set;
    public void SetState1() {
        if(!state1Set) {
            state1Set = true;
            //...other code
            changeState(1);
        }
    }

    static bool state2Set;
    public void SetState2() {
        if(!state2Set) {
            state2Set = true;
            //...other code
            changeState(2);
        }
    }

    static bool state3Set;
    public void SetState3() {
        if(!state3Set) {
            state3Set = true;
            //...other code
            changeState(3);
        }
    }
}

使用公共连接对象和不同连接状态运行单元测试用例

1 个答案: