通过sql query

Question

我有以下数据。

ColumnA   ColumnB
1234      1
1234      2
1234      3
1235      2
1236      2
1237      1
1237      2
1238      1
1238      3
1238      5

我需要输出如下所示，它只显示列中1个具有相同值的项目（例如ColumnA）

ColumnA   ColumnB
1234      1
1234      2
1234      3
1237      1
1237      2
1238      1
1238      3
1238      5

实际上我通过下面的查询获得了第一个表，如何根据最终表格对其进行修改？

select ColumnA, ColumnB
from TableX 
group by ColumnA, ColumnB
--having COUNT(ColumnA) > 1 
--having COUNT(ColumnB) > 0
order by ColumnA asc

更新

在查询下方运行会在下面的表格中显示，但如果我可以按照原始请求运行，那将会很棒...

SELECT b.ColumnA
(
    select ColumnA, ColumnB
    from TableX 
    group by ColumnA, ColumnB
    --having COUNT(ColumnA) > 1 
    --having COUNT(ColumnB) > 0
    -- order by ColumnA asc
) b 
group by b.ColumnA
having COUNT(b.ColumnA) > 1

结果查询是：

ColumnA 
1234      
1237      
1238      

更新

就是这样！如果还有其他解决方案，请告诉我......

   SELECT c.*
   FROM TableX c
   WHERE c.ColumnA IN
   (
     SELECT b.ColumnA
     (
        select ColumnA, ColumnB
        from TableX 
        group by ColumnA, ColumnB
        --having COUNT(ColumnA) > 1 
        --having COUNT(ColumnB) > 0
        -- order by ColumnA asc
      ) b 
      group by b.ColumnA
      having COUNT(b.ColumnA) > 1
    )

Answer 1

如果我的理解是正确的，您只想在columnA值重复时输出行：

declare @tableX table
(
  ColumnA int,
  columnB int
)

insert into @tableX
values 
(1234,      1 ),
(1234,      2 ),
(1234,      3 ),
(1235,      2 ),
(1236,      2 ),
(1237,      1 ),
(1237,      2 ),
(1238,      1 ),
(1238,      3 ),
(1238,      5 )


select ColumnA, columnB
from @tableX x
where exists (select 1 from @tableX where ColumnA = x.ColumnA group by ColumnA having COUNT(*) > 1);