我有一个js AJAX,它获取一些内容并将其插入名为content_holder的html元素中。我想在使用ajax更新内容后立即调用函数。我试图将On Pointer Up
元素添加到已添加的内容中,但似乎它没有被执行。所以我希望有人在这里知道解决方案。 (我不使用jQuery)
<script>
&#13;
function ajax(instruction, push, url, callback){
var xmlhttp; // the object for the httprequest
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() { // every time the readystate changes
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) { // status 200 = sucessfull page! NOT 404! // 1 2 3 4 are states of the request (4 is when it's done)
var content = xmlhttp.responseText + "<script>ajaxDone();</script>";
callback(content); // goes to the callback function (from the argument "callback") and then passes the xmlhttp
}
};
xmlhttp.open(instruction,url,true); // sends a the var q to the next php file
xmlhttp.send(''); // Sends the request
if(push == true){ // Change the link to the url of the ajax with
var urlPath = window.location.protocol + "//" + window.location.host + window.location.pathname; // where the host is on
if(url == "home.php"){ // If it's the starting page REMOVE THE ?p= !!
var urlPath = window.location.protocol + "//" + window.location.host + window.location.pathname;
window.history.pushState({path:urlPath},'','./'); // an empty url push (!REMOVE THE DOT WHEN THE SITE IS HOSTED PROPERLY)
return; // exit's the function
}else{}
var newLink = "?p=" + url; // Gives us the link we want except that we don't want the .php
newLink = newLink.substring(0, newLink.indexOf('.')); // makes a new string with character 0 to the dot! Will not include the ending of the file
window.history.pushState({path:urlPath},'',newLink); // the push
}
else{}
}
&#13;
答案 0 :(得分:1)
请看一下这个主题:How to make an AJAX call without jQuery?
你可以这样做:
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == XMLHttpRequest.DONE ) {
if(xmlhttp.status == 200){
document.getElementById("myDiv").innerHTML = xmlhttp.responseText;
//here you call whichever function you want
}
.....
}
希望有所帮助