Question

我有一个文件，我试图在jinja模板中显示它。我正在尝试将此negxxx string xxxneg的字符串替换为<span class="SomeCssClass_neg_xxx"> string </span>。问题在于我正在使用的匹配组编号\1。我知道我有多场比赛不仅1.需要一些帮助。

import re
StringIn = 'negxxx data1 xxxneg  out of span negxxx data2 xxxneg negzzz data1 zzzneg  out of span negzzz data2 zzzneg'
StringIn = re.sub(r"negxxx(.*)xxxneg", r"<span class='neg_xxx'>\1</span>" , StringIn)
StringIn = re.sub(r"negzzz(.*)zzzneg", r"<span class='neg_zzz'>\1</span>" , StringIn)
print StringIn

我明白了：

<span class='neg_xxx'> data1 xxxneg  out of span negxxx data2 </span> <span class='neg_zzz'> data1 zzzneg  out of span negzzz data2 </span>

这是不正确的，我需要的是：

<span class='neg_xxx'> data1 </span>   out of span <span class='neg_xxx'> data2 </span><span class='neg_zzz'> data1 </span>  out of span <span class='neg_zzz'> data2 </span>

Answer 1

你的.*正在竞争到字符串的末尾，只备份到最近的（到字符串结尾）＆＃34; xxxneg＆＃34;。使用惰性量词.*?，它一次只吃一个字符然后尝试匹配模式的其余部分：

import re
StringIn = 'negxxx data1 xxxneg  out of span negxxx data2 xxxneg negzzz data1 zzzneg  out of span negzzz data2 zzzneg'
StringIn = re.sub(r"negxxx(.*?)xxxneg", r"<span class='neg_xxx'>\1</span>" , StringIn)
StringIn = re.sub(r"negzzz(.*?)zzzneg", r"<span class='neg_zzz'>\1</span>" , StringIn)
print StringIn

python regex用匹配的字符串替换所有出现

1 个答案: