Question

我正在尝试使用以下代码从图像中读取文本，但它的响应为400.

我已将图像保存在本地计算机上的c-drive中

我也将密钥隐藏在下面的代码中。

下面是我使用vision api编写的函数

    private static String postingtogoogle() throws Exception {
     //    Base64.encode;
    String re = "";
    String url = "https://vision.googleapis.com/v1/images:annotate?key=mykey";
    URL obj = new URL(url);
    HttpsURLConnection con = (HttpsURLConnection) obj.openConnection();
    BufferedImage img = ImageIO.read(new File("C:/a.png"));
    String imgstr = encodeToString(img, "png");

    imgstr = encodeToString(img, "png");

    //add reuqest header
    con.setRequestMethod("POST");

    con.setRequestProperty("Accept-Language", "en-US,en;q=0.5");

    String urlParameters = "{\n"
            + "  \"requests\":[\n"
            + "    {\n"
            + "      \"image\":{\n"
            + "        \"content\":\"" + imgstr + "\"\n"
            + "      },\n"
            + "      \"features\":[\n"
            + "        {\n"
            + "          \"type\":\"LABEL_DETECTION\",\n"
            + "          \"maxResults\":1\n"
            + "        }\n"
            + "      ]\n"
            + "    }\n"
            + "  ]\n"
            + "}";

    // Send post request
    con.setDoOutput(true);
    DataOutputStream wr = new DataOutputStream(con.getOutputStream());
    wr.writeBytes(urlParameters);
    wr.flush();
    wr.close();

    BufferedReader in = new BufferedReader(
            new InputStreamReader(con.getInputStream()));
    String inputLine;
    StringBuffer response = new StringBuffer();

    while ((inputLine = in.readLine()) != null) {
        response.append(inputLine);
    }
    in.close();

    re = response.toString();

    return re;
}

Answer 1

添加以下行：

con.setRequestProperty("Content-Type", "application/json; charset=UTF-8");

使用谷歌视觉api阅读图像文本

1 个答案: