Question

我有2个数组。数组1返回不同的数字。例如：（29,30）。数组2有对象。例如：

    ({
        IDCode = 5;
        dateEnd = "04/08/2016";
        dateStart = "04/08/2016";
    },
        {
        IDCode = 30;
        dateEnd = "04/09/2016";
        dateStart = "04/09/2016";
    },
    {
        IDCode = 55;
        dateEnd = "04/10/2016";
        dateStart = "04/10/2016";
    })

我想将第一个数组与第二个数组的IDCode进行比较。如果它们匹配，我想制作一个只有匹配数字的新数组。如果使用上面的例子，我只会返回array3

    {
        IDCode = 30;
        dateEnd = "04/09/2016";
        dateStart = "04/09/2016";
    }

我做了一个返回IDCode == {"29", "30"}的谓词但是我没有匹配。

我想我必须创建一个循环，只测试第二个数组的valueForKey，但我不知道从哪里开始。任何帮助都会很棒！

Answer 1

您必须执行以下代码行之类的操作。使用 IN 。

 NSPredicate *intersectPredicate = [NSPredicate predicateWithFormat:@"ANY IDCode IN(%@), otherArray];
 NSArray *result = [your_array filteredArrayUsingPredicate:intersectPredicate];

参考链接：http://ronnqvi.st/array-intersections-and-differences/

<强>更新

{{1}}

参考链接：NSPredicate for Array of Dictionaries

Answer 2

很容易使用NSMutableSet

NSMutableSet *set1 = [NSMutableSet setWithArray: array1];
NSSet *set2 = [NSSet setWithArray: array2];
[set1 intersectSet: set2];
NSArray *resultArray = [set1 allObjects];

希望它会有所帮助：）

 NSArray *arr = @[ @{ @"IDCode" : @"5",
                     @"dateEnd" : @"04/08/2016",
                     @"dateStart" : @"04/08/2016"} ,
                  @{ @"IDCode" : @"30",
                     @"dateEnd" : @"04/09/2016",
                     @"dateStart" : @"04/09/2016"},
                  @{ @"IDCode" : @"55",
                     @"dateEnd" : @"04/10/2016",
                     @"dateStart" : @"04/10/2016"}];
NSArray *ar2 = @[@{ @"IDCode" : @"5",
                    @"dateEnd" : @"04/08/2016",
                    @"dateStart" : @"04/08/2016"}];

NSMutableSet *set1 = [NSMutableSet setWithArray: arr];
NSSet *set2 = [NSSet setWithArray: ar2];
[set1 intersectSet: set2];
NSArray *resultArray = [set1 allObjects];

它对我有用......

Answer 3

这是你的解决方案!!效率也很高。

NSArray *IDCodeArray = @[@29, @30, @31];
NSArray *dataArray = @[
                       @{
                           @"IDCode" : @5,
                           @"dateEnd" : @"04/08/2016",
                           @"dateStart" : @"04/08/2016"
                       },
                       @{
                           @"IDCode" : @30,
                           @"dateEnd" : @"04/09/2016",
                           @"dateStart" : @"04/09/2016"

                       },
                       @{
                           @"IDCode" : @55,
                           @"dateEnd" : @"04/10/2016",
                           @"dateStart" : @"04/10/2016"
                       },
                       @{
                           @"IDCode" : @29,
                           @"dateEnd" : @"04/11/2016",
                           @"dateStart" : @"04/11/2016"
                        }
                       ];

NSMutableArray *resultArray = [[NSMutableArray alloc] init];


// loop through each object using fast enumeration

[IDCodeArray enumerateObjectsUsingBlock:^(NSNumber *idcode, NSUInteger idx, BOOL * _Nonnull stop) {

    __block NSUInteger foundIndex = NSNotFound;

    // loop through data array to find IDcode
    foundIndex = [dataArray indexOfObjectPassingTest:^BOOL(NSDictionary  *dictObject, NSUInteger idx, BOOL * _Nonnull stop) {

        // stop the loop if found
        NSUInteger IDCodeObject = [dictObject valueForKey:@"IDCode"];
        return (IDCodeObject.integerValue == idcode.integerValue);
    }];

    // add object to result array if found
    if(foundIndex != NSNotFound){
        [resultArray addObject:[dataArray objectAtIndex:foundIndex]];
    }
}];

NSLog(@"Result Array : %@", resultArray);

===================================

查找包含重复代码的所有匹配值

// loop through each object using fast enumeration

[IDCodeArray enumerateObjectsUsingBlock:^(NSNumber *idcode, NSUInteger idx, BOOL * _Nonnull stop) {

    // loop through data array to find IDcode

    [dataArray enumerateObjectsUsingBlock:^(NSDictionary  *dictObject, NSUInteger index, BOOL * _Nonnull stop) {

        NSUInteger IDCodeObject = [[dictObject valueForKey:@"IDCode"] integerValue];

        if(IDCodeObject == idcode.integerValue){
            [resultArray addObject:[dataArray objectAtIndex:index]];
        }

    }];

}];

比较1个对象数组和第二个数组比较按键

3 个答案: