Question

男人我以为我拥有它！我一直在研究Vigenere问题并且已经接近但在我检查时仍然遇到此错误。当密钥必须循环回来时，看起来有问题。想法？

这是错误：

:) vigenere.c exists

:) vigenere.c compiles

:) encrypts "a" as "a" using "a" as keyword :( encrypts "world, say hello!" as "xoqmd, rby gflkp!" using "baz" as keyword \ expected output, but not "xoqmj, yfz gflkp!\n"

:( encrypts "BaRFoo" as "CaQGon" using "BaZ" as keyword \ expected output, but not "CaQAun\n"

:( encrypts "BARFOO" as "CAQGON" using "BAZ" as keyword \ expected output, but not "CAQAON\n"

:) handles lack of argv[1]

:) handles argc > 2

:) rejects "Hax0r2" as keyword

这是我的代码：

#include <stdio.h>
#include <cs50.h>
#include <stdlib.h>
#include <ctype.h>
#include <string.h>

#define FALSE 0
#define TRUE 1

int main(int argc, string argv[])
{
    string key = argv[1];

    if (argc!= 2)
    {
        printf("please provide only one perameter \n");

        // stop the program
        return 1;
    }

    // iterate over the key to make sure its all alpha  
    int i,j;
    for (i = 0, j = strlen(key); i < j; i++)
    {
        if (!isalpha(key[i]))
        {
            printf("please use only alphanumeric values \n");
            return 1;
        }
    }

    // now we have a key, "key" from the ONE perameter that is all alpha

    string message = GetString();
    int k = 0;
    int keyindex;

    for (i = 0, j = strlen(message); i < j; i++, k++)
    {
        if (isalpha(message[i]))
        {
            keyindex = k % strlen(argv[1]);
            // covering the upper case letters
            if (isupper(message[i]))
            {
                // covering the upper case letters with upper case key letters

                if isupper(key[i])
                {
                    // print cipher according to two upper case
                    int cipher = ((message[i] - 65 + key[keyindex] - 65) % 26)
                        + 65;
                    printf("%c", cipher);
                }
                else
                {
                    // print according to upper case message lower case key
                    int cipher = ((message[i] - 65 + key[keyindex] - 97) % 26)
                        + 65;
                    printf("%c", cipher);
                }
            }
            // this is for the non upper case letters
            if (islower(message[i]))
            {
                if isupper(key[i])
                {
                    // print cipher according to lower case message and
                    // upper case key letter
                    int cipher = ((message[i] - 97 + key[keyindex] - 65) % 26)
                        + 97;
                    printf("%c", cipher);
                }
                else
                {
                    // print according to lower case message  and lower case key
                    int cipher = ((message[i] - 97 + key[keyindex] - 97) % 26)
                        + 97;
                    printf("%c", cipher);
                }
            }

        }
        // non alpha symbols
        else
        {
            printf("%c", message[i]);
        }
    }

    // end program after iterating
    printf("\n");

}

Answer 1

您的计划出现问题：

1）Sytax错误应该阻止它编译：

if isupper(key[i]) - ＆gt; if (isupper(key[i]))

其中有两个，所以一定要修复它们。

2）递增k

int k = 0;
...
for (i = 0, j = strlen(message); i < j; i++, k++)
{
    if (isalpha(message[i]))
    {
        keyindex = k % strlen(argv[1]);

有两个要接近这个，要么在字符上增加k ，要么在每个字母上增加k。这个问题的设计者选择 letter ，所以我们需要这样做：

int k = 0;
...
for (i = 0, j = strlen(message); i < j; i++)
{
    if (isalpha(message[i]))
    {
        keyindex = k++ % strlen(argv[1]);

3）现在我们已经定义了keyindex：

if isupper(key[i]) - ＆gt; if isupper(key[keyindex])

其中有两个，所以一定要修复它们。

应用这些更改和一些样式清理，我们得到：

#include <stdio.h>
#include <cs50.h>
#include <stdlib.h>
#include <ctype.h>
#include <string.h>

int main(int argc, string argv[])
{
    if (argc != 2)
    {
        printf("please provide only one parameter \n");

        return 1; // stop the program
    }

    string key = argv[1];

    // iterate over the key to make sure it's all alpha  

    for (int i = 0, j = strlen(key); i < j; i++)
    {
        if (!isalpha(key[i]))
        {
            printf("please use only alphanumeric values \n");

            return 1;
        }
    }

    // now we have a key, "key" from the ONE parameter that is all alpha

    string message = GetString();

    for (int i = 0, k = 0, j = strlen(message); i < j; i++)
    {
        if (isalpha(message[i]))
        {
            int keyindex = k++ % strlen(key);

            if (isupper(message[i])) // covering the upper case letters
            {
                if (isupper(key[keyindex]))
                {
                    // print cipher according to both upper case
                    int cipher = ((message[i] - 'A' + key[keyindex] - 'A') % 26) + 'A';
                    printf("%c", cipher);
                }
                else
                {
                    // print cipher according to upper case message and lower case key
                    int cipher = ((message[i] - 'A' + key[keyindex] - 'a') % 26) + 'A';
                    printf("%c", cipher);
                }
            }
            else // this is for the non upper case letters
            {
                if (isupper(key[keyindex]))
                {
                    // print cipher according to lower case message and upper case key letter
                    int cipher = ((message[i] - 'a' + key[keyindex] - 'A') % 26) + 'a';
                    printf("%c", cipher);
                }
                else
                {
                    // print cipher according to both lower case
                    int cipher = ((message[i] - 'a' + key[keyindex] - 'a') % 26)  + 'a';
                    printf("%c", cipher);
                }
            }

        }
        else // non alpha symbols
        {
            printf("%c", message[i]);
        }
    }

    printf("\n"); // end program after iterating

}

您的代码复制了许多可以与微小变化相结合的逻辑 - 重复逻辑是难以发现错误的一种方式。

CS50 Vigenere - 输出不正确

1 个答案: