Question

我试图从每一行添加它们但它不起作用

import csv

FILE_NAME = "paintingJobs.txt" #I use this so that the file can be used easier
COL_HEADERS = ['Number', 'Date', 'ID', 'Total', 'Status', 'Paid']
NUM_COLS = len(COL_HEADERS)#This will insure that the header of each column fits into the length of the data

# read file once to determine maximum width of data in columns
with open(FILE_NAME) as f:
    reader = csv.reader(f, delimiter=',')
    # determine the maximum width of the data in each column
    max_col_widths = [len(col_header) for col_header in COL_HEADERS]
    for columns in reader:
        for i, col in enumerate(columns):
            if "A" in columns and int(columns[5]) < int(columns[3]):
                max_col_widths[i] = max(max_col_widths[i], len(repr(col)))
    # add 1 to each for commas
    max_col_widths = [col_width+1 for col_width in max_col_widths]

# read file second time to display its contents with the headers
with open(FILE_NAME) as f:
    reader = csv.reader(f, delimiter=',')
    # display justified column headers
    print(' ' + ' '.join(col_header.ljust(max_col_widths[i])
                            for i, col_header in enumerate(COL_HEADERS)))
    # display justified column data
    for columns in reader:
        if "A" in columns and int(columns[5]) < int(columns[3]):
            print(columns)
            print ("Amount_Outstanding:"),
            print (int(columns[3]) - int(columns[5])),

这是结果：

Number   Date          ID      Total   Status  Paid  
['E5345', '22/09/2015', 'C106', '815', 'A', '400']
Amount_Outstanding:
415
['E5348', '23/09/2015', 'C109', '370', 'A', '200']
Amount_Outstanding:
170
['E5349', '25/09/2015', 'C110', '480', 'A', '250']
Amount_Outstanding:
230
['E5353', '28/09/2015', 'C114', '272', 'A', '200']
Amount_Outstanding:
72
['E5355', '29/09/2015', 'C116', '530', 'A', '450']
Amount_Outstanding:
80
['E5363', '01/10/2015', 'C124', '930', 'A', '500']
Amount_Outstanding:
430
['E5364', '02/10/2015', 'C125', '915', 'A', '800']
Amount_Outstanding:
115
['E5367', '03/10/2015', 'C128', '427', 'A', '350']
Amount_Outstanding:
77
['E5373', '10/10/2015', 'C134', '1023', 'A', '550']
Amount_Outstanding:
473

所以我想知道我是否可以将每个Amount_Outstanding的总数加起来并将其更改为另一个变量，记住我是python和csv的新手

Answer 1

您可以通过创建＆＃39; outstanding_amount＆＃39;来解决此问题。列表，您可以在其中输入所有未付金额并获胜：D

#build the list
outstanding_amount = []

# read file second time to display its contents with the headers
with open(FILE_NAME) as f:
    reader = csv.reader(f, delimiter=',')
    # display justified column headers
    print(' ' + ' '.join(col_header.ljust(max_col_widths[i])
                            for i, col_header in enumerate(COL_HEADERS)))
    # display justified column data
    for columns in reader:
        if "A" in columns and int(columns[5]) < int(columns[3]):
            print(columns)
            print ("Amount_Outstanding:")
            print (int(columns[3]) - int(columns[5]))

            ###### NEW PART ######
            outstanding_amount.append(int(columns[3]) - int(columns[5]))

# Show the sum of all collected outstanding amount
print (sum(outstanding_amount))

您甚至可以通过执行此类操作来访问数据集。

例如，如果您想知道第二项的未付金额。然后你做：

print outstanding_amount[1] # Since we start from 0, the second item is at index 1

有没有办法添加我从.txt文件中检索的整数

1 个答案: