我对# Create a figure instance
fig = plt.figure(1, figsize=(4, 4))
# Create an axes instance
ax = fig.add_subplot(111)
ax.set_ylim([0, 1.2])
# Create the boxplot
bp = ax.boxplot(data_to_plot,widths=(0.5, 0.5))
plt.setp(bp['boxes'], linewidth=1)
# Save the figure
plt.xticks([1, 2], ['A', 'B'],fontsize=16)
plt.yticks(fontsize=16)
#fig.savefig('fig1.png', bbox_inches='tight')
plt.show()
表达式有一个奇怪的问题,{{json_req}}
和{{密码}}表达式运行良好,我可以看到我在live中所做的更改。
但无论我在登录名和密码输入中写了什么,{{pseudo}}
表达式都没有发生。
我想这是我的一个基本错误,但我现在有点迷失了这个:/。
感谢您的帮助:)
的login.html
{{json_req}}
LoginCtrl.js
<div class="row">
Pseudo : {{pseudo}}
</div>
<div class="row">
Password : {{password}}
</div>
<div class="row">
json : {{json_req}}
</div>
<div class="row">
<label class="float-center">
Pseudo
<input ng-model="pseudo" type="text" required>
<span class="form-error">
Pseudo Missing.
</span>
</label>
</div>
<div class="row">
<label class="float-center">
Password
<input ng-model="password" type="password" required>
<span class="form-error">
Password Missing.
</span>
</label>
</div>
答案 0 :(得分:1)
这是预期的行为。当你写:
$scope.json_req = {
pseudo: $scope.pseudo,
password: $scope.password
};
您为$scope.pseudo
和$scope.password
创建值的“快照”。稍后更改模型时,它们不会更新。
当$scope.$watch
或json_req
更改(不是真正推荐)时,您可以设置pseudo
并更新password
。或者我建议,在范围内写一个getter函数:
Object.defineProperty($scope, 'json_req', {
get: function() {
return {
pseudo: $scope.pseudo,
password: $scope.password
}
}
});
答案 1 :(得分:0)
试试这个:
angular.module("asdfapp",[]).service("User",function(){}).controller('LoginCtrl', ['$scope', 'User',
function ($scope, User) {
$scope.json_req = {
pseudo: "",
password: ""
};
$scope.LoginUser = function () {
if ($scope.json_req.pseudo != undefined
&& $scope.json_req.password != undefined) {
User.login($scope.json_req).then(function (data) {
$scope.response = data;
$scope.json_req = {};
});
} else
console.log("UNDEFINED");
};
}]);
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="asdfapp" ng-controller="LoginCtrl">
<div class="row">
Pseudo : {{json_req.pseudo}}
</div>
<div class="row">
Password : {{json_req.password}}
</div>
<div class="row">
json : {{json_req}}
</div>
<div class="row">
<label class="float-center">
Pseudo
<input ng-model="json_req.pseudo" type="text" required>
<span class="form-error">
Pseudo Missing.
</span>
</label>
</div>
<div class="row">
<label class="float-center">
Password
<input ng-model="json_req.password" type="password" required>
<span class="form-error">
Password Missing.
</span>
</label>
</div>
</div>
答案 2 :(得分:0)
好的,我找到了解决方案。并且预计这是我的一个愚蠢的错误xD
我应该写ng-model =“json_req.pseudo”而不是ng-model =“pseudo”来填充json_req对象:/
很抱歉打扰了你们!
由于