我在使用spring data jpa存储库执行自定义查询时遇到问题。
@Query annitated方法没有指定List<>的参数。类型。
这里是实体类:
@Entity
@Table(name = "\"user\"")
public class User {
@Id
@GeneratedValue(generator = "increment")
private long id;
@Column(unique = true, nullable = false)
private String mail;
@ManyToMany(targetEntity = Interest.class, mappedBy = "users")
private List<Interest> interests = new ArrayList<Interest>();
...
... setters and getters.
@Entity
@Table(name = "interest")
public class Interest {
@Id
@Column(name = "interest_name", nullable = false, unique = true)
private String name;
@ManyToMany(targetEntity = User.class, fetch = FetchType.LAZY)
private List<User> users = new ArrayList<User>();
...
... setters and getters.
这里是查询:
@Repository
public interface UserRepository extends JpaRepository<User, Long> {
@Query("select distinct u from User u where u <> :currentUser and
u.interests in :currentInterests")
List<User> getUsersWithSameInterests(@Param("currentUser") User user,
@Param("currentInterests") List<Interest> interests);
}
我用过这个:
@Autowired
private UserRepository userRepository;
@Override
public List<User> getUsersWithSameInterests(User user) {
return userRepository.getUsersWithSameInterests(user, user.getInterests());
}
但得到了
org.springframework.dao.InvalidDataAccessResourceUsageException: could not extract ResultSet; SQL [n/a]; nested exception is org.hibernate.exception.SQLGrammarException: could not extract ResultSet
.
.
.
Caused by: java.sql.SQLException: No value specified for parameter 2
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:957)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:896)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:885)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:860)
at com.mysql.jdbc.PreparedStatement.checkAllParametersSet(PreparedStatement.java:2205)
at com.mysql.jdbc.PreparedStatement.fillSendPacket(PreparedStatement.java:2185)
at com.mysql.jdbc.PreparedStatement.fillSendPacket(PreparedStatement.java:2115)
at com.mysql.jdbc.PreparedStatement.executeQuery(PreparedStatement.java:1936)
at org.apache.commons.dbcp2.DelegatingPreparedStatement.executeQuery(DelegatingPreparedStatement.java:83)
at org.apache.commons.dbcp2.DelegatingPreparedStatement.executeQuery(DelegatingPreparedStatement.java:83)
at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.extract(ResultSetReturnImpl.java:70)
... 73 more
虽然第二参数具有有效值
,但没有为参数2指定值答案 0 :(得分:0)
Change the code as per below:
Old Code:
`@Repository
public interface UserRepository extends JpaRepository<User, Long> {
@Query("select distinct u from User u where u <> :currentUser and
u.interests in :currentInterests")
List<User> getUsersWithSameInterests(@Param("currentUser") User user,
@Param("currentInterests") List<Interest> interests);
}`
Updated Code:
`@Repository
public interface UserRepository extends JpaRepository<User, Long> {
@Query("select distinct u from User u where u.user :currentUser
and u.interests in :currentInterests")
List<User> getUsersWithSameInterests(@Param("currentUser") User user,
@Param("currentInterests") List<Interest> interests);
}`