Question

我从另一篇文章中借用了一些代码，所以我意识到col1指定对我的例子来说不是必需的，但基本上这只需要在选择某个主题（工资单，税收等）时填充某些员工信息。。）：

HTML：

<table class="table table-bordered table-striped">
    <tr>
        <th>
            <select class="col1 selectTopic">
                <option>Payroll</option>
                <option>Tax</option>
                <option>Accounts Payable</option>
            </select>
        </th>
    </tr>
    <tr>
        <td class="col1 name"></td>
    </tr>
    <tr>
        <td class="col1 photo"></td>
    </tr>
      <tr>
        <td class="col1 email"></td>
    </tr>
      <tr>
        <td class="col1 phone"></td>
    </tr>
</table>

使用Javascript：

var data = {
    "contacts":
{
        "contact": [
{
            "name": "Payroll",
            "photo": "Emp 1 Photo",
            "email": "emp1@mysite.com",
            "phone": "4113834848"},
{
            "name": "Tax",
            "photo": "Emp 2 Photo",
            "email": "emp2@mysite.com",
            "phone": "4113834848"},
{
            "name": "Accounts Payable",
            "photo": "Emp 3 Photo",
            "email": "emp3@mysite.com",
            "phone": "4113834848"},
]}
}

$(".selectTopic").change(function() {
    var jthis = $(this);
    var whichCol;
    if (jthis.hasClass("col1")) {
        whichCol = "col1";
    }
    $.each(data.topics.topic, function(i, v) {
        if (v.name == jthis.val()) {
            $("td." + whichCol + ".name").html(v.name);
            $("td." + whichCol + ".photo").html(v.photo);
            $("td." + whichCol + ".email").html(v.email);
            $("td." + whichCol + ".phone").html(v.phone);
            return;
        }
    });

});

Answer 1

您有data.topics.topic，我相信您需要data.contacts.contact

https://jsfiddle.net/qfy397jt/

您知道如何在浏览器中使用开发人员工具/控制台吗？它会向您显示此错误的原因（data.topics未定义）。 https://developers.google.com/web/tools/chrome-devtools/iterate/inspect-styles/shortcuts?hl=en如果您还没有使用Dev。之前的工具！

Javascript：基于DropDown列表填充表

1 个答案: