Question

嗨，我一直在为经典的策划游戏编码。当没有重复的钉子时，该程序似乎完美地工作。

public static void guessingNumber(int [] digits){
    print("Guess 5 digits numbers! ps.you only have 7 tries");
    boolean guess = true;
    int n = 0;
    while(guess){ n++;
    print("");
    print("Guess no." + n + "!");
    int [] yourGuess = manualNumber();
    int correctPosition = 0;
    int correctNumber = 0;
    for(int i = 0; i<yourGuess.length; i++){
        if(digits[i] == yourGuess[i]){
            correctPosition += 1;
        } else if(contains(digits, yourGuess[i]) && digits[i] != yourGuess[i]){
            correctNumber += 1;
        }

    }
    print("You have " + correctPosition + " correct place and " + correctNumber + " correct numbers.");
    if(Arrays.equals(digits, yourGuess)){
        guess = false;
        print("");
        print("Well Done! You did it!");
        }
    else if(n==10){
        guess = false;
        print("");
        print("Game Over! You lose.");
    }
    }
}
public static void main(String[] args){
showMainMenu();
selectMode();

}
}

接下来我应该做什么才能允许重复钉？另外，我需要为cpu编写一个算法来猜测我的数字。欢迎提出建议！

Answer 1

我对人类与CPU模式的认识（笑话:)）

private static void runHumanVsCPU() {
    int[] digits = manualNumber();
    System.out.println("Guess no.1!\n"+digits[0]+digits[1]+digits[2]+digits[3]+digits[4]+"\nCPU have 5 correct place and 0 correct numbers.\n\nWell Done! CPU did it!");
}

P.S。为什么＆＃34; ps.you只有7次尝试＆＃34;但是

} else if (n == 10) {
    guess = false;
    print("");
    print("Game Over! You lose.");
}

具有重复钉子的Mastermind（仅编辑重要部件）

1 个答案: