Question

我有一个SQL Server查询：

SELECT MD.Author_ID, MD.CoAuthor_ID, ACP.Probability [AC_Probability], 
       MD.Venue_ID, AVP.Probability [AV_Probability], A2P.pid [Paper_ID],
       P.abstract_research_area_category_id [Paper_Category_ID], 
       MD.Paper_Count, MD.Year
FROM   Merged_Data MD
JOIN   sub_aminer_author2paper A2P    ON MD.Author_ID = A2P.aid AND
                                      MD.Year      = A2P.p_year AND
                                      MD.Venue_ID  = A2P.p_venue_vid
JOIN   sub_aminer_paper P             ON MD.Venue_ID  = P.p_venue_vid AND
                                      MD.Year      = P.p_year
JOIN   AuthorCoAuthorProbability ACP  ON MD.Author_ID = ACP.Author_ID AND
                                      MD.CoAuthor_ID = ACP.CoAuthor_ID AND
                                      MD.Year      = ACP.Year
JOIN   AuthorVenueProbability    AVP  ON MD.Venue_ID = AVP.Venue_ID AND
                                      MD.Author_ID = AVP.Author_ID AND
                                      MD.Year      = AVP.Year
WHERE  MD.Author_ID = 677 AND 
       P.abstract_research_area_category_id IS NOT NULL AND 
       A2P.pid = P.pid

给我结果如下：

我想在P_Probability列之前的末尾添加另一列Year，例如：

对于Year = 2005，Author_ID = 677在8列中有11，12和Paper_Category_ID，而3中有Paper_Count 1}}列，每个Year每个Author_ID最多有3行（如果存在）。

因此P_Probability列中的值应为：

8对677 / 2005 = Paper_Count = 1/3的{3}行的{3}行中存在0.333333333333333的次数
11对677 / 2005 = Paper_Count = 1/3的{3}行的0.333333333333333次存在的次数
12对677 / 2005 = Paper_Count = 1/3

的{3}行的{3}行中存在0.333333333333333次的次数

换句话说，P_Probability计算概念是：

DISTINCT Paper_Category_ID中Author_ID的{{1}}除以Year中的Paper_Count除以Year

的次数

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如何在SQL Server中添加自定义计算列

0 个答案: