Question

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.10/angular.min.js"></script>
<div ng-app='app' ng-controller='ctrl'>
  <button ng-click='addGrade()'>Add</button>
  <div style="border-style: solid; width: 200px" ng-repeat='grade in grades'>
    <label for="select{{$index}}">Grade {{$index}}:</label>
    <select id='select{{$index}}' ng-model='grade.list'>
      <option value="grade1">Grade 1</option>
      <option value="grade2">Grade 2</option>
      <option value="grade3">Grade 3</option>
      <option value="grade4">Grade 4</option>
    </select>
    <br>
    <label for="text{{$index}}">Text{{$index}}:</label>
    <input id='text{{$index}}' type="text" ng-model='grade.text' size='10' />
  </div>
  {{grades}}
</div>

我收到错误消息：

否＆＃34;楼层＆＃34;候选人产生预期的语境结果类型＆＃34; Int＆＃34;

我进口了达尔文。

Answer 1

HashSet<Integer> zipcodeSet = new HashSet<Integer>(Arrays.asList(zipcodeList)); duplicates = zipcodeSet.size()!=zipcodeList.length;取一个Double并返回另一个Double。如果您希望它成为Int（与floor匹配，则必须明确转换它：self.maxViewers。

Answer 2

使用round(_:)方法

使用指定的舍入将值舍入为整数值规则。

var w1 = 6.5
w1.round()
// w1 == 7.0

// Equivalent to the C 'round' function:
var w = 6.5
w.round(.toNearestOrAwayFromZero)
// w == 7.0

// Equivalent to the C 'trunc' function:
var x = 6.5
x.round(.towardZero)
// x == 6.0

// Equivalent to the C 'ceil' function:
var y = 6.5
y.round(.up)
// y == 7.0

// Equivalent to the C 'floor' function:
var z = 6.5
z.round(.down)
// z == 6.0

不能使用＆＃34; floor＆＃34;在迅速

2 个答案: